Page 111 - ICSE Chemistry 8
P. 111

In reactants           In products
                             Number of H atoms:                      2                      2

                             Number of Cl atoms:                     2                      2

                             The chemical equa  on, H  + Cl   2HCl, now contains an equal number of various atoms
                                                       2
                                                            2
                             in reactants and products. Therefore, we can say that it is a balanced equa  on.

                      Take a Break!

                     Balance the following chemical equa  ons.

                      1.  CO  + H O  H CO     3
                                 2
                            2
                                             2
                      2.  H  + O   H O
                                          2
                                2
                           2
                      3.  H  + N   NH    3
                                2
                           2
                      4.  Fe + HCl  FeCl  + H  2
                                              2
                      5.  Fe + H O  Fe O  + H   2
                                               4
                                             3
                                2
                 Applying the Law of Conservation of Mass
                 The law of conserva  on of mass states that ma  er is neither created nor destroyed in a chemical reac  on.
                 This law can be applied to the atomic masses of reactants and products to balance the chemical equa  on.
                 Let’s understand this with the help of the following examples.

                 Example 1:  Balance the following equa  on.

                                                         CaCO   CaO + CO       2
                                                              3
                 Solu  on:    The above equa  on is balanced as it consists of equal number of various atoms on both the
                              sides.

                              Here, the reactants and products are compounds. In this case we fi nd out the molecular
                              mass of compounds by using the atomic mass of each element.
                              The atomic masses of all the elements are shown below.

                              Ca = 40 u, C = 12 u, O = 16 u
                              By using these atomic masses, we can fi nd the atomic masses of the compounds involved in
                              the reac  on.

                                    CaCO  = 40 + 12 + 3 × 16 = 40 + 12 + 48 = 100 u
                                          3
                                      CaO = 40 + 16 = 56 u

                                       CO  = 12 + 2 × 12 = 44 u
                                          2
                              Total mass of the reactant on LHS = 100 u

                              Total mass of the products on RHS = 56 + 44 = 100 u
                              Therefore, the total mass of the reactants is equal to the total mass of the products which
                              conforms to the law of conserva  on of mass.



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