Page 147 - Start Up Mathematics_7
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Example 23: In the adjoining figure:
                                                                                  A                      C
                          (a)  Is ∠3 adjacent to ∠4?
                                                                                              1
                          (b)  Is ∠COE adjacent to ∠COB?                                            2

                          (c)  Does ∠COE and ∠EOD form a linear pair?                  5    O
                                                                                                  3          E
                          (d)  Are ∠BOD and ∠DOA supplementary?
                          (e)  Is ∠1 vertically opposite to ∠4?                               4
                          (f)  Which angle is vertically opposite to ∠5?            D                     B
                          (g)  Are ∠1 and ∠3 vertically opposite angles?

            Solution:     (a)  Yes, ∠3 and ∠4 are adjacent.
                          (b)  No, ∠COE and ∠COB are not adjacent.
                          (c)  Yes, ∠COE and ∠EOD form a linear pair.                      1       2
                          (d)  Yes, ∠BOD and ∠DOA are supplementary.                                 3
                          (e)  Yes, ∠1 and ∠4 are vertically opposite angles.            5       4
                          (f)  ∠COB is vertically opposite to ∠5.
                          (g)  No, ∠1 and ∠3 are not vertically opposite angles.
            Example 24: Indicate all pairs of angles that form:
                          (a)  Vertically opposite angles
                          (b)  Linear pair
            Solution:     (a)  ∠3 and ∠5; ∠4 and (∠1 + ∠2) are vertically opposite angles.
                          (b)  ∠4 and ∠5; ∠3 and ∠4 are linear pairs.

            Example 25: Find the values of the angles x, y and z in each of the following:



                                        y


                                 105°        x
                          (a)                                        (b)                 x

                                        z                                            30°
                                                                                                  z
                                                                                           y


            Solution:     (a)  x = 105°                                   (Vertically opposite angles)
                               y + 105° = 180°                            (Linear pair)

                               ∴ y = 75°
                               z = y = 75°                                (Vertically opposite angles)
                          (b)  30° + y = 180°                             (Linear pair)
                               ⇒ y = 150°

                               z = 30°                                    (Vertically opposite angles)
                                 (30° + x) + 90° = 180°                   (Linear pair)

                               ⇒ 30° + x = 90°
                               ⇒ x = 90° – 30° = 60°


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