Page 23 - Start Up Mathematics_8 (Non CCE)
P. 23

−3   4    7   −12
                    Example 34:  Find     ×   ×    ×     .
                                       5    6   15     8
                                  −3   4    7    −12    (−3 ) ×××4 7  (−12 )  ()−× ××1  1 7  (−2 )
                    Solution:        ×   ×    ×       =                    =
                                   5   6   15     8        56       ×           51
                                                                                 ×× ×52
                                                             ××15 8
                                                        ()−× ××1  1 7  ()−1  7
                                                      =                  =
                                                            ×× ×51
                                                           51              25

                      EXERCISE 1.7

                      1.  Verify a × b = b × a for:
                                 11      −7              −3       −12                       8               17
                          (a)  a =  ,  b =       (b)  a =   ,  b =         (c)  a =−9,  b =         (d)  a =   ,  b = 0
                                 15       6               4        5                       27               23
                      2.  Verify a × (b × c) = (a × b) × c for:

                                 6      −9      1                           3     −7                 27            −5
                          (a)  a = ,  b =  ,  c =          (b)  a =−5,  b = ,  c =          (c)  a =   ,  b = 0,  c =
                                 7       4      2                           2      20                43             6
                                 −13       −20      −5             10             3                  6      2     −14
                         (d)  a =    ,  b =    ,  c =      (e)  a =   ,  b = 2,  c =        (f)  a = ,  b = ,  c =
                                  15       26        4             17             5                  7      3      15
                      3.  Verify a × (b + c) = (a × b) + (a × c) for:
                                 5      −4      −7                  −7      6      13                −1      4      −2
                          (a)  a = ,  b =  ,  c =           (b)  a =   ,  b = ,  c =        (c)  a =   ,  b = ,  c =
                                 6       5      10                   3      5      12                2       3      7
                      4.  Using distributive property of multiplication of rational numbers over addition/subtraction, simplify
                         the following:
                              −15    3  12          2   − 3  4              6     2  6           −2     −4  11 
                          (a)     ×   +        (b)    ×    −           (c)    ×   +          (d)    ×    −    
                               4     7  5           5   8    5             11   3   − 7           3    7    9  

                      5.  Find the multiplicative inverse (or reciprocal) of the following:
                                  7               15                 −21                 4    − 2 
                          (a)  −×3           (b)                 (c)                 (d)   ×          (e)  0
                                   4              37                  38                 5     3 
                               75                                    −30
                          (f)                (g)  –1             (h)
                              − 63                                   −19
                      6.  Fill in the missing rational numbers. Also state the property used.
                              3    − 4  8    3  _____   8        28    − 17    − 17   ______
                                            =
                          (a)   ×     ×       ×        ×     (b)     ×      =       ×
                              7     5   9   7           9         31    19      19 
                              135    _______    − 135                −8     2   7     −8  2     −8  _______ 
                                                                                    =
                          (c)     ×           =                  (d)     ×    +        ×     +    ×        
                              − 56               56                  11     5  12   11   5    11           
                              46  _______                            −19 _______
                          (e)    ×         =  0                  (f)     ×          =1
                              63                                      25
                      7.  Simplify the following and express the result in the lowest form:

                              5   − 6   11   − 4               −2    −28    5    3               6     4    39
                          (a)   ×     ×    ×               (b)    ×      ×     ×   × 9      (c)     ×     ×    ×  2
                              8   20    18   33                7     15    −4    8               13   27    24




                                                                                                                    15
   18   19   20   21   22   23   24   25   26   27   28