Page 21 - Start Up Mathematics_8 (Non CCE)
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p    q      q   p         q                                                    p
                            1
                    q  ×  p  = =  p  ×  q  , where   p   is called the multiplicative inverse (or reciprocal) of   q  .
                            q                              p       p                                  q
                       l  If    is the multiplicative inverse of    then    is also the multiplicative inverse of   .
                             p                             q       q                                  p
                       l  Zero has no reciprocal.
                       l  Reciprocal of ‘1’ is ‘1’ and reciprocal of (–1) is (–1).

                                                                     −13                                 8
                    Example 28: Find the multiplicative inverse of: (a)     (NCERT)    (b) –6    (c)
                                                                     19                                  7
                                                                 −13    −19
                    Solution:    (a)  The multiplicative inverse of   =     .
                                                                 19      13
                                 (b)  The multiplicative inverse of  −=6  −1 .
                                                                      6
                                                                     7
                                 (c)  The multiplicative inverse of   8  = .
                                                                 7   8
                    VI. Multiplication by Zero

                    “The product of any rational number with ‘0’ is always ‘0’.”
                          p                           p             p
                    So, if    is a rational number, then   ×= =×0  0  0  .
                          q                           q             q
                                           −3                          4                                −9
                    Example 29:  Find: (a)    × 0                 (b)    × 0                       (c)     × 0
                                            5                          7                                −11

                    Solution:     (a)   −3 ×=0  0                 (b)  4  ×=  0                    (c)  −9  ×=0  0
                                                                           0
                                       5                               7                                −11
                    VII. Distributive Property of Multiplication Over Addition
                    “Multiplication of rational numbers is distributive over addition.”
                          p r       u
                    So, if   ,   and    are three rational numbers, then
                          q   s     v
                                     p    r   u     p  r      p  u 
                                    q  ×     s  +  v   =     q  ×  s     +     q  ×  v  .
                                                
                                                                       
                         The multiplication of rational numbers is also distributive over subtraction.
                          p r u                                   p     r   u     p  r     p  u 
                            ,,
                         If   q s v   are three rational numbers, then   q  ×     s  −  v     =     q  ×  s     −    q  ×  v   
                                                                                             
                    Example 30:  Verify that:
                                     3    − 1 5    3  − 1    3 5            2     2  7   2 2     2  7 
                                 (a)   ×    +     =   ×    +    ×       (b)   ×    −       ×      ×   
                                                                                                 =
                                                                                                           −
                                     4     3  6    4   3     4 6            3     5  10   3 5    3 10 
                                                              1
                                                            ()
                                                                  15
                                     3   − 1  5    3  { 2×− +×      }
                    Solution:    (a)   ×    +    =   ×                                                     2   3, 6
                                     4   3    6    4         6
                                                                                                             3   3, 3
                                                           25 
                                                     3   −+       3   3   9   3                                 1, 1
                                                  =    ×         =  ×  =    =
                                                     4     6     4   6   24  8
                                                                                                               LCM = 6

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