Page 193 - Start Up Mathematics_7
P. 193
Solution: (a) In ∆ ADB and ∆ ADC
AD = AD (common)
∠ ADB = ∠ADC (each 90°)
AB = AC (given)
(b) Yes, ∆ ADB ∆ ADC (by RHS congruence criterion)
(c) Yes, BD = CD, as the corresponding sides of congruent triangles are equal.
(d) Yes, ∠BAD = ∠CAD, as the corresponding angles of congruent triangles are equal.
Example 17: In the given figure, BD AC, CE AB and BD = CE.
(a) State any three pairs of equal parts in ∆ CBD and ∆ BCE.
(b) Is ∆ CBD ∆ BCE? If yes, name the criteria used.
(c) Name an equal angle corresponding to ∠DCB.
(d) How many other pairs of congruent triangles are there in the figure?
Solution: (a) In ∆ CBD and ∆ BCE,
∠D = ∠E (each 90°)
A
(common)
(given)
(b) ∆ CBD ∆ BCE (by RHS congruence criterion) E D
(c) ∠EBC
(d) 2 pairs (one can use tracing paper to locate them).
B C
Example 18: Prove the following triangles congruent. Which congruence
criterion do you use?
D
E
B E
(a) (b)
F
A C D A B C
L H
N
R Z
F
(c) (d) M G
P Q X Y
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