Page 34 - ICSE Math 8
P. 34

Properties of negative integral exponents

                    The laws of exponents hold good for negative integral exponents of a rational numbers. Let us understand it
                    with the help of the following examples.
                                                                          p
                    Example 1:    Express each of the following in the form   q .

                                                             − 
                                  (a)  (4) –4           (b)   3  −4        (c)    1
                                                            
                                                             5                   2 () − 3
                                         –4
                    Solution:     (a)  (4)   =   1  =     1      =   1                                        x − n  =  1 n  
                                                       ×××
                                               4 () 4  4444        256                                             x  
                                                                                                                      n 
                                                                                                          
                                        − 
                                       3   −4    1         1                                                 x  n  x 
                                  (b)       =         =                                                      =   
                                       5       3  4    (− 3) 4                                               y 
                                                                                                                      n
                                                                                                              y
                                                 − 
                                                                                                                       
                                                           4
                                                 5       5 ()
                                                 ()5  4       5555               625
                                                               ×××
                                              =       =                         =
                                                         −
                                                           ) ( 3 × −
                                                                        ) ( 3
                                                 −
                                                ( 3 ) 4  ( 3 × −  ) ( 3 × −   )   81
                                        1       1                                                                   1  
                                                        3
                                  (c)       =      = (2)  = 2 × 2 × 2 = 8                                    x − n  =  n 
                                        2 () − 3  1                                                                x  
                                               2 () 3
                    Example 2:  Write each of the following as a rational number with positive exponent.
                                                        –5
                                         –7
                                 (a)  {(3)  ÷ (3) –10 } × (3)            (b)    −  1  −5  ×    −  1  −7
                                                                             
                                                                              5       5  
                                         –7
                    Solution:    (a)  {(3)  ÷ (3) –10 } × (3) –5
                                                                                                                       
                                     =    1  ÷  1   ×  1                                               ()x  − n  =  1 n 
                                                                                                        
                                                 10 
                                       
                                         3 () 7  3 ()    3 () 5                                                 ()x  
                                                                  10
                                         1     3 ()    1      3 ()    1
                                                  10
                                                    
                                       
                                                              
                                                                     
                                     =      ×       ×     =        ×
                                                                   7
                                          3 () 7  1   3 () 5     3 ()   3 () 5
                                                                     
                                                    
                                                                              −
                                                                               2
                                     =  3 (  10 7−  ) ×  1  = () 3  1  =  3 () 3 −    5  =  3 ()        ()x  m  =  ()x  m −    n 
                                                       3 ×
                                                                                                      
                                                                                                                       
                                                 3 () 5      3 () 5                                     ()x  n        
                                                                                                                       
                                                                                                                      n
                                                     1
                                         1     1 () 2    2                                              ()x  n    x 
                                                                                                        
                                     =      =     =                                                         =     
                                                     3
                                        3 () 2  3 () 2                                                   ()y  n    y 
                                                                                                                       
                                      −  1  −5   −  1  −7  1   1       1       1
                                 (b)       ×      =        ×       =       ×
                                                                            1
                                                                                   1
                                      5      5       − 1 5   − 1 7  − () 5  − () 7
                                                                         5       7
                                                          5      5     5 ()    5 ()
                                                      =   ()5  5  ×  ()5  7  =  ()5  5 +    7  =  ()5  12
                                                                                   −
                                                                −
                                                         −
                                                        ()1  5  ()1  7  ()1  5 +    7  () 1  12
                                                                        −
                                                        ()5  12   12
                                                      =       = (5)       { (negative number) even power  = positive number}
                                                          1
                                                         1  2
                    Example 3:  By what number should       be multiplied to get the product as 15?
                                                         3 
                    Solution:    Let the required number be x.
                                  1  2                  1  2
                                     × x = 15  ⇒  x ×      = 15  ( Multiplication is commutative)
                                  3                     3 
                 22
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