Page 37 - ICSE Math 8
P. 37

25 × ()p  − 4     ()5  2  1   () p  − 4
                    Solution:    (a)                    =       ×    ×
                                      5 () − 3  ×  10 × ()p  − 8  ()5  − 3  10  () p  − 8

                                                                                                       m
                                                                              4
                                                                ( 3
                                                                                                              n
                                                        = ()5  2  −−  )  ×  1  ×  ()p  −−  ( 8−  )  { (x)  ÷ (x)  = (x) m – n }
                                                                     10
                                                                                     5
                                                        = ()5  2 +  3  ×  1  ×  ()p  − 4 +  8  =  ()5 ×  1  ×  ()p  4
                                                                   10          4     4  5 ×  2
                                                                  1
                                                        = ()5  5 −  1 ×× () =p  4  () 5 × ()p  =  625  p 4
                                                                  2             2         2
                                      ()3  − 5  ×  ()10  − 5  × 125  ()3  − 5  ×  (5 ×  ) 2  − 5  ×  ()5  3  ()3  − 5  × ()5  − 5  ×  ()2  − 5  ×  ()5  3
                                 (b)                     =                       =
                                         ()5  − 7  ×  ()6  − 5  ()5  − 7  ×  (3 2×  ) − 5  () 5  −77  ×  3 () − 5  ×  2 () − 5
                                                         =  (3) –5 – (–5)  × (5) –5 + 3 – (–7)  × (2) –5 – (–5)
                                                                                                              n
                                                                                 m
                                                                                                       m
                                                                                       n
                                                                          { (x)  × (x) = (x) m + n  and (x)  ÷ (x)  = (x) m – n }
                                                         =  (3) –5 + 5  × (5) –2 + 7  × (2) –5 + 5
                                                                                    5
                                                                                                                   0
                                                                          0
                                                              0
                                                                    5
                                                         =  (3)  × (5)  × (2)  = 1 × (5)  × 1                { (x)  = 1}
                                                              5
                                                         =  (5)  = 3,125
                                                              EXERCISE 2.2
                      1.  Evaluate.                                              −2                    − 3
                               –2
                         (a)  (3)               (b)  (–5) –4           (c)    −  1          (d)   2 
                                                                            
                                                                                                    
                                                       p                     4                    5 
                      2.  Write the following in the form   q  .
                                                              2
                                                                                     5 
                         (a)    3  − 1        (b) ( − ) ×6  −1    −1  (c)   3  − 1 ×     − 1
                                                                             
                              
                                                              
                              5                                          5     2 
                                                              3
                      3.  Simplify.
                                                                                                            –1
                                       –1 2
                                                                                                      –1
                                                                          –1
                                –1
                                                                                –1 –1
                                                           –1 –1
                                                                                          –1
                                                     –1
                         (a)  {(5)  × (4) }   (b)  {(5)  ÷ (6) }   (c)  {(2)  × (3) }  × (4)   (d)  {(4)  – (5) } ÷ (3) –1
                      4.  Find the reciprocal of the following.
                               1  − 1  3          2  − 2    3  − 4    4  −2   4  −3   4  5
                                                                                                − 
                                                                                       − 
                                                                              − 
                         (a)                (b)      ÷          (c)       ×      ÷    
                               4                  3      2            7      7      7  
                      5.  Write each of the following as a rational number with negative exponent.              3
                                                                                                           2
                                                                                                            
                                                                                                        3 
                         (a)  (7) 4             (b)    4  6           (c)     2  3  − 2   (d)        − 1 
                                                                                                               
                                                      
                                                                                                      
                                                                                
                                                                             
                                                      9                      3                      4    
                                                                                                               
                      6.  Write each of the following as rational number with positive exponent.
                              4  − 3                 1  − 2  3           3  − 3  − 4         –5     3     –4
                         (a)                  (b)                 (c)                 (d)  (8)  × (8)  × (8)
                              3                      5                   7   
                      7.  Simplify.                                                                    −1
                                                                                           
                                                                                                  2
                                                                                                   
                                             4 
                                                 7 
                                            −
                                                                                                      
                         (a)    3  2  ×  1  ×  3 () ×    − 1  (b)   3  − 2  +   2  − 2  +   1  − 2   (c)         −  1   −2 
                              
                                                                
                                                                        
                                                                                
                              2   4 − 4         3           4     3     2             3     
                                                                                                      
                                        4 
                                                                                                            
                             (
                                                                 1 
                                                                                                      3 
                               2
                                  3
                                   2
                         (d)  5 − ) ×     − 3           (e)       − 1 ×− (  25) − 1   − 1    (f)      1  3      2  ÷   2  − 1  3
                                                                                               ×
                                                                                           
                                                                                                               
                                         3                     5                       3       2     3   
                                                  –1
                                                                                        –1
                      8.  By what number should (3)  be multiplied to get the product as (–6) ?
                                                                                                                        25
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