Page 186 - ICSE Math 8
P. 186

Example 8:    The diagonals of a rectangle DENT intersect at point O.   D                         E
                                  If –EON = 50º, find –ODT?                                  2
                    Solution:     In rectangle DENT, diagonals DN and ET intersect at
                                  point O, therefore,                                                  1  O  50º
                                  –1 = –EON          (Vertically opposite angles)
                                                                                             3
                                  fi –1 = 50º                                                T                         N

                                  Also, diagonal ET = diagonal DN (Diagonals of a rectangle are equal)
                                     1
                                                         1
                                  fi   ET = OT = OE and   DN = OD = ON
                                     2                   2
                                  fi OD = OT
                                  Now in D DOT, OD = OT (proved)
                                  fi –2 = –3                                       (Angles opposite to equal sides are equal)

                                  Also, –1 + –2 + –3 = 180º                             (Angle-sum property of a triangle)
                                  fi 50º + –2 + –3 = 180º  fi 2–2 = 180º – 50º = 130º
                                           130∞
                                  fi –2 =         = 65º
                                            2
                                  Therefore, –2 = –ODT = 65º
                    Example 9:    ABC is a right-angled triangle and O is the midpoint of the side opposite to the right angle.
                                  Explain why O is equidistant from A, B and C.
                    Solution:     Draw AD || BC and DC || AB to meet at D. Join OD.            A                      D
                                  Therefore, ABCD is a rectangle.
                                  Since in a rectangle, diagonals are equal and they bisect
                                  each other, so OA = OB = OC = OD.                                       O
                                  fi O is equidistant from A, B and C.

                                                                                               B                      C


                                                             EXERCISE 16.3

                                                                                            E                       C
                      1.  PACE is a rectangle. Give reasons for the following:
                         (a)  PC = AE                   (b)  ∠APC = ∠CEA
                         (c)  OA = OE = OP = OC         (d)  ∠POA = ∠COE                                  O
                      2.  In a square, one diagonal is 16 cm. Find the side of the square.
                      3.  In a rectangle CALM, CA = 4 cm and AL = 3 cm. Find the            P                       A
                        length of the diagonals CL and AM.
                      4.  In a rectangle KITE, diagonal KT = 13 cm, IT = 5 cm.                     D                 C
                        Find KI, KE and ET.
                      5.  In the figure given alongside, ABCD is a square. Find x.                          85°
                      6.  The sides of a rectangle are in the ratio 4 : 5. If the perimeter of the rectangle   O
                        is 90 cm, find its sides.                                                       x
                      7.  Name the quadrilaterals whose diagonals:                                 A     E           B
                         (a) bisect each other.
                         (b)  are perpendicular bisectors of each other.
                         (c) are equal.


                174
   181   182   183   184   185   186   187   188   189   190   191