Page 41 - Start Up Mathematics_8 (Non CCE)
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
                                                               − 
                                                                                                                       n
                                                                                                                n
                                                                                                          n
                                         −3
                    Solution:    (a)  (−8 ) ×    −  1  −3   =  −×8   1  −3                   { (x)  × (y)  = (xy) }
                                                         
                                                              
                                              2             2  
                                                                    ) 1
                                                                                      ) 1
                                                           (−8 ) × (−  −3    (−4 ) × (−  −3    4 − 3  − 3
                                                      =                =              =       =  4 ()
                                                              2               1           1 
                                               –4
                                                      –4
                                         4
                                                                                                                       n
                                                                                                          n
                                                                                                                n
                                                              4
                                 (b) (–2)  × (3)  × (5)   = (–2)  × (3 × 5) –4                      { (x)  × (y)  = (xy) }
                                                              4
                                                        = (–2)  × (15) –4
                                                                                                                      n
                                                                                                                       
                                                                                                        
                                                                                  − 
                                                               4
                                                                                                                       
                                                        = (−2 ) ×   1  =  (−2 ) 4  =   2  4             ()x  n n  =    x 
                                                                                                        
                                                                                 
                                                                                                                   
                                                                  15
                                                                  () 4   ()  4    15                     ()y    y 
                                                                          15
                                                                                                                       
                                            − 4       − 4       5  − 4                                                n
                                                                                                                       
                                                  2 
                                                                                                        
                                       32   5   () 5  5    2     5                                 ()x  n    x 
                                                           
                                 (c)        =        =                                                 =     
                                      243       3 () 5       3                                     ()y  n    y 
                                                                                                                       
                                                         4 
                                                 2
                                                   5 ×        − 5      2  − 4                        m n    mn
                                              =          =                                          { (x )  = (x) }
                                                 3           3 
                                                                                                        m
                                                                                                              n
                                               –10
                                         –7
                                                        –5
                                 (d) {(3)  ÷ (3) } × (3)  = {(3) –7 – (–10) } × (3) –5            { (x)  ÷ (x)  = (x) m – n }
                                                          = {3 –7 + 10 } × (3) –5
                                                                                                              n
                                                                                                        m
                                                               3
                                                                     –5
                                                          = (3)  × (3)  = (3) 3 + (–5)           { (x)  × (x)  = (x) m + n }
                                                          = (3) –2
                    Example 8:  Simplify:                                                             −1
                                                         2
                                                          
                                                                                                 2
                                                                                                  
                                      2  3   2  − 2      1   − 2  1                   −   −2 
                                                                                              1
                                 (a)     ×    ×      ×                      (b)           
                                      3    3         2     24                          6      
                                         − 3     − 3     − 3
                                        1 
                                                       
                                                         1 
                                              
                                                1 
                                      
                                 (c)       −     ÷  
                                     
                                                         5
                                         4    3   
                                                    
                                                      1 
                                                     
                    Solution:    (a)   2  3 ×  2  − 2  ×   2  − 2  1   =   2  3 +−   (  2)  ×  1  2 ×−   (  2)  ×  1
                                                    
                                                           ×
                                      
                                             
                                                                                 
                                                                      
                                      3    3        2    24   3        2        24
                                                                                           m
                                                                                                 n
                                                                                                              m n
                                                                                                                     mn
                                                                                    {  (x)  × (x)  = (x) m + n ; (x )  = (x) }
                                                                                                  2
                                                                 1 
                                                       =   2  1 ×    − 4 ×  1   =   2  ×  2 () 4  ×  1  =  2 × () 4  × 1  =  2 () 5  × 1
                                                          
                                                          3     2   24    3         24      324×       324×
                                                             2
                                                          2 ××××        2    32        4    4
                                                                 2
                                                                    2
                                                       =                  =        =      =
                                                              324×          324      33×    9
                                                                             ×
                                          2  −2  −1    2  ( −2) ××− ( 1 )
                                                          1
                                          1
                                                                                                                     mn
                                                                                                              m n
                                 (b)      −      =     −                                  { (x )  = (x) }
                                              
                                                             
                                            
                                                           
                                            6           6    
                                                            −  1  2  2   −  1  2  × 2
                                                                                                                     mn
                                                                                                              m n
                                                          
                                                       =         =                                 { (x )  = (x) }
                                                             6      6  
                                                                                                                    33
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