Page 246 - Start Up Mathematics_8 (Non CCE)
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Construction of Quadrilateral Given Its Three Angles and Two Included Sides

                    Example 9:      Construct a quadrilateral MARS in which MA = 5.2 cm,
                                    AR = 3.8 cm, –M = 100º, –A = 65º and –R = 130º.
                                                                                                    S
                    Solution:       Construction: Draw a rough sketch of the figure to be
                                    constructed.                                                                     R
                                                                                                               130º
                                    Steps of Construction:                                                            3.8 cm
                                    1.  Draw a line MA = 5.2 cm.                                        100º      65º
                                                                                                      M     5.2 cm    A
                                       M          5.2 cm      A
                                                                                           X
                                                                                                              Y

                                    2.   At point M on line MA, draw  –AMX =
                                       100º.  Also  at point  A  on  line  MA,  draw
                                       –MAY = 65º using a protractor.
                                    3.    Taking A as centre and radius = 3.8 cm, draw
                                       an arc on line AY intersecting it at point R.               100º          65º
                                                       X                                        M       5.2 cm        A
                                                                         Y
                                                                           R


                                                                                           X

                                                                                           S                 Y
                                                                              3.8 cm
                                                                                                               R
                                                              100º           65º
                                                           M         5.2 cm        A                       130º   3.8 cm



                                    4.    At point R on line AR, draw –ARS = 130º
                                       using a protractor intersecting line MX at S.              100º           65º
                                       Join RS.                                                 M       5.2 cm        A

                                    Hence, MARS is the required quadrilateral.

                    Example 10:     Construct a parallelogram HEAR in which HE = 5 cm, EA = 6 cm and –R = 85º.   (NCERT)

                    Solution:       Construction: Draw a rough sketch of the
                                    figure to be constructed.                                   H                   R
                                    You know that opposite angles of a                                          85º
                                    parallelogram are equal.                              5 cm
                                                                                                                   5 cm
                                    \ –E = –R = 85º
                                                                                              85º             95º
                                    Also, EA ÍÍHR and AR is the transversal.               E         6 cm        A
                                    \ –A + –R = 180º
                                                    ( Interior angles on the same side of the transversal are supplementary.)
                                    fi –A + 85º = 180º
                                    fi –A = 180º – 85º = 95º
                                    \ –A = 95º


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