Page 200 - Start Up Mathematics_8 (Non CCE)
P. 200

Example 4:      Find the compound interest on ` 1,000 for 2 years at the rate of 10% per annum compounded
                                    annually.

                    Solution:       Here, P = ` 1,000, R = 10%, n = 2 years

                                         Ê    R  ˆ n
                                    A = P 1+ 100¯
                                         Á
                                                 ˜
                                         Ë
                                             Ê    10 ˆ 2       Ê 110ˆ  2
                                       = 1,000 1+ 100¯  = 1,000 Á Ë 100¯ ˜
                                                     ˜
                                             Á
                                             Ë
                                                Ê 11ˆ 2
                                       = 1,000 ×  Á 10¯   = 1,210
                                                    ˜
                                                Ë
                                    Now, C.I. = A – P = ` (1,210 – 1,000) = ` 210
                    Example 5:      The simple interest on a certain sum of money at the rate of 4% per annum for 3 years is
                                    ` 1,200. Find the compound interest on the same amount at the rate of 10% per annum for
                                    3 years.
                    Solution:       Let the principal (P) be ` x.

                                                        PR T¥  ¥
                                    We know that, S.I. =
                                                          100

                                               x ¥¥43         12x
                                    fi 1,200 =            fi         = 1,200
                                                 100          100
                                          1 200 100,  ¥
                                    fi x =             = 10,000
                                              12

                                    \ Principal (P) = ` 10,000

                                      Now,  P =  ` 10,000, R = 10%, n = 3 years

                                                Ê    R  ˆ n          Ê    10 ˆ  3
                                          A =  P 1+ 100¯   = ` 10,000 1+ 100¯ ˜
                                                        ˜
                                                Á
                                                                     Á
                                                Ë
                                                                     Ë
                                                       Ê
                                                            1 ˆ
                                            =  ` 10,000  1+ 10¯ ˜ 3  = ` 10,000 Ê Á Ë 11ˆ ˜  3
                                                       Á
                                                                            10¯
                                                       Ë
                                                 Ê         11   11   11ˆ
                                            =  `  10 000,  ¥  10  ¥  10  ¥  10¯   = ` 13,310
                                                 Á
                                                                       ˜
                                                 Ë
                                    Hence, C.I. = A – P = ` (13,310 – 10,000) = ` 3,310
                    Example 6:      Find the difference in the simple interest and the compound interest on ` 625 for 2 years at
                                    the rate of 4% per annum.

                    Solution:       P = ` 625, T = 2 years, R = 4% per annum
                                             PR T¥  ¥    625 42¥¥
                                    \ S.I. =           =            = ` 50
                                               100          100


                     192
   195   196   197   198   199   200   201   202   203   204   205