Page 100 - Start Up Mathematics_8 (Non CCE)
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                    Example 20:     Multiply (3x  + y ) and (2x  – 3y ) using the column method.
                                          2
                    Solution:           3x  + y 2
                                        2
                                    ¥  2x  – 3y 2
                                        4
                                                                               2
                                              2 2
                                        6x  + 2x y          Æ  (Multiply by 2x )
                                              2 2
                                                                                 2
                                    +        – 9x y – 3y 4   Æ  (Multiply by –3y  and write like terms one below the other)
                                        4
                                             2 2
                                                     4
                                     6x  – 7x y  – 3y       Æ  (Adding like terms)
                                                                    2
                    Example 21:     Find the product of (5x + 4) and (x  – 3x) and verify the result for x = –2.
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                                                                2
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                    Solution:       (5x + 4) ¥ (x  – 3x) = (5x) ¥ (x  – 3x) + 4 ¥ (x  – 3x)
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                                                              2
                                                      = (5x ¥ x ) – (5x ¥ 3x) + (4 ¥ x ) – (4 ¥ 3x)
                                                                 2
                                                          3
                                                                      2
                                                      = 5x  – 15x  + 4x  – 12x
                                                          3
                                                                 2
                                                      = 5x  – 11x  – 12x
                                    To verify for x = –2
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                                                                                    2
                                    LHS = (5x + 4) ¥ (x  – 3x) = {5 ¥ (–2) + 4} ¥ {(–2)  – 3(–2)}
                                                             = (–10 + 4) ¥ (4 + 6) = (–6) ¥ 10 = –60
                                                                 3
                                             3
                                                   2
                                                                           2
                                    RHS = 5x  – 11x  – 12x = 5(–2)  – 11(–2)  – 12(–2)
                                                          = 5 ¥ (–8) – 11 ¥ 4 + 24
                                                          = –40 – 44 + 24 = –84 + 24 = –60
                                    \  LHS = RHS
                                    Hence verified.
                    Example 22:     Simplify: (2x + 3)(3x – 2) – (x – 4)(2x + 1)
                    Solution:       (2x + 3)(3x – 2) – (x – 4)(2x + 1)
                                          = {2x(3x – 2) + 3(3x – 2)} – {x(2x + 1) – 4(2x + 1)}
                                          = (2x ¥ 3x) – (2x ¥ 2) + (3 ¥ 3x) – (3 ¥ 2) – [{(x ¥ 2x) + (x ¥ 1)} – {(4 ¥ 2x) + (4 ¥ 1)}]
                                                                 2
                                              2
                                          = 6x  – 4x + 9x – 6 – {2x  + x – 8x – 4}
                                                             2
                                              2
                                          = 6x  + 5x – 6 – {2x  – 7x – 4}
                                              2
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                                          = 6x  + 5x – 6 – 2x  + 7x + 4
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                                                    2
                                          = (6x  – 2x ) + (5x + 7x) + (–6 + 4)          (Combining like terms and adding)
                                              2
                                          = 4x  + 12x – 2
                    Multiplication of a binomial by a trinomial and a trinomial by a trinomial
                    multiplication of a binomial by a trinomial and a trinomial by a trinomial can be done in the same way as
                    multiplication of a binomial by a binomial.
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                    Example 23:     Multiply: (a) (x  – 3x + 5) by (4x – 6)     (b) (p  + 2p – 3) by (q  – pq – 4)
                    Solution:       (a)  Using column method
                                         2
                                         x  – 3x + 5
                                        4x – 6
                                          3
                                                 2
                                        4x  – 12x  + 20x       Æ  (Multiply by 4x)
                                                2
                                       +        – 6x  + 18x – 30   Æ  (Multiply by –6 and write like terms one below the other)
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                                        4x  – 18x  + 38x – 30   Æ  (Adding like terms)
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