Page 27 - ICSE Math 8
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−5                                   7
                      5.  By what number should     be multiplied to get the product as   ?
                                                14                                  12
                                                −12                  3
                      6.  By what number should      be divided to get  ?
                                                35                   7

                                          −12      13                   −1      31
                      7.  Divide the sum of    and     by the product of    and   .
                                           7        5                   2       7
                                          8      12
                      8.  Divide the sum of   and    by their difference.
                                          3      7
                    Rational Numbers on a Number Line
                    Rational numbers include positive and negative numbers besides 0. The number line representing them extends
                    indefi nitely on both sides of 0. We have rational numbers between –1, 0; 0, 1; 1, 2; and so on.


                              –4        –3       –2        –1        0         1         2         3        4
                    If the segment between each pair of consecutive integers is divided into two equal parts, we get the following
                    series of rational numbers:
                                                −   −8  −7  −6  −5  −4  −3   −2  1 0 1 2 3 4
                                             ...,   ,  ,   ,   ,   ,   ,   ,   ,,,,,         ,...
                                                 2   2   2   2   2   2   2   2 2 2 2 2 2
                    This series of rational numbers can be represented on a number line as follows:
                                  –8   –7  –6   –5  –4   –3   –2   –1    0   1    2    3    4   5    6    7    8
                                  2    2   2    2    2    2    2    2    2   2    2    2    2   2    2    2    2



                                  –4       –3       –2        –1         0        1         2        3         4
                    If the segment between each pair of consecutive integers is divided into three equal parts, we get the following
                    series of rational numbers:
                                               −   −6  5  −   3 −  2  −4 −  1 0 1 2 3 4 5 6
                                            ...,   ,  ,    ,   ,   ,    ,  ,  ,  ,  ,  ,  ,  , ...
                                                3   3   3    3   3    3  3 3 3 3 3 3 3
                    This series of rational numbers can be represented on a number line as follows.
                       –9   –8   –7   –6   –5   –4   –3   –2   –1   0    1    2    3    4    5    6    7    8    9
                       3    3    3    3    3    3    3    3    3    3    3    3    3    3    3    3    3    3    3



                      –3             –2             –1              0              1              2              3
                    Example 32:  Represent the following rational numbers on a number line.
                                      7                                          −5
                                 (a)                                         (b)
                                      4                                           2
                                      7   3           3
                    Solution:    (a)   = 1   ⇒ 11<      <  2
                                      4   4           4
                                      3
                                     1  lies between 1 and 2. Since we have 4 in the denominator, we divide the part between
                                       4                                                                      7
                                     1 and 2 into 4 equal parts. Starting from 1, the third part to its right represents  .
                                                                                 3  7                          4
                                                                                1  =
                                                                                 4  4



                                                  0                  1                   2


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