Page 33 - ICSE Math 4
P. 33

Finding the Missing Digits

                    Let’s understand how to fi nd the missing digits in an addi  on sum by considering the

                    given example.
                    Example 5:  Find the missing digits.

                                   Th  H  T  O

                                      ?    3    ?   4

                                  +  6 2 5           ?
                                      8    ?    4   1


                    Solu  on:     Step 1:  Look at the ones column.                                 Th  H  T  O
                                            1 is smaller than 4.                                                 1
                                                                                                       ?    3    ?    4
                                            So, we fi nd the smallest number which
                                            when added to 4 gives a sum which has 1                +  6 2 5 7

                                            in the ones place.                                         8    ?    4    1
                                            11 is the smallest number with 1 in the ones place.

                                              Thus, 4 +  ?  = 11.

                                            Now, 11 – 4 = 7 (sum – one addend = other addend).
                                            So, we write 7 in the blank space.

                                              Since 11 is a 2-digit number, keep the 1 as it is and carry over 1 to the
                                            tens place.

                                  Step 2:  Look at the tens column.

                                            1 +   ?  + 5 = 4


                                            6 +   ?  = 4

                                            4 is smaller than 6.

                                            So, we fi nd the smallest number which                   Th  H  T  O
                                            when added to 6 gives a sum which has 4                         1    1
                                                                                                       ?    3 8 4
                                            in the ones place.

                                            14 is the required number.                             +  6 2 5 7
                                                                                                       8    ?    4    1
                                            Thus, 6 +  ?  = 14.

                                            Now, 14 – 6 = 8 (sum – one addend = other addend).

                                            So, we write 8 in the blank space.

                                              Since 14 is a 2-digit number, keep 4 as it is and carry over 1 to the
                                            hundreds place.

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