Page 60 - Start Up Mathematics_8 (Non CCE)
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                                                2
                    Using the identity, (x + y)  = x  + 2xy + y 2
                                                            2
                                                    2
                                                                              2
                                        2
                                   (108)  = (100 + 8)  = (100)  + 2(100)(8) + (8)  = 10,000 + 1,600 + 64 = 11,664
                                                   2
                                           \ (108)   = 11,664
                                                                        2
                                                             2
                                                         2
                         Sometimes using the identity (x – y)  = x  – 2xy + y  makes it easier to find the square of a number. For
                        example, if we wish to find the square of 98, first we write 98 as 98 = 100 – 2.
                    3. Diagonal Method
                    Diagonal method is applicable to two or more digit numbers.

                    Step 1:   Let there be a number x say, 23. It has 2 digits. Draw twice the number
                              of squares, i.e., 2 × 2 = 4 squares. Divide each square by a diagonal        2        3
                              into two parts.

                    Step 2:   Starting from top left square, write the number along the side of the   2
                              squares vertically and horizontally. Remember each digit of the number
                              occupies one square.                                                    3
                    Step 3:   Multiply each digit on the left of the square with the digit on the top      2        3
                              and place the product in the corresponding square.
                                                                                                      2  0
                              The square has been divided into two parts by the diagonal. The tens           4
                              digit of the product should be placed above the diagonal and the units   3
                              digit below the diagonal in that square.


                        If the product is a single digit number, place 0 in the space above the diagonal.


                    Step 4:   Repeat the multiplication                                                    2        3
                              i.e.,  (a)  Row 1 × Column 1, Row 1 × Column 2, ...                     2  0        0
                                   (b)  Row 2 × Column 1, Row 2 × Column 2, ...                              4        6
                                                                                                     3  0   6   0   9
                                   and so on.
                    Step 5:   Starting from right bottom, add the digits diagonally. If the sum            2        3
                              is a two-digit number, encircle the units digit and carry over the      2  0        0
                              tens digit to the sum of the next diagonal.                                    4        6
                    Step 6:   Arrange the encircled digits starting from extreme left. This   0  0    3  0       0
                              gives the square of the given number.                             4            6       9
                                    2
                               \ (23)  = 529                                                    0         6
                                                                                              + 1         0        9
                    Easy Methods of Finding Squares                                             5        + 6
                                                                                                         1 2
                    1. For numbers ending in 5
                    The rule says, ‘‘One more than previous’’.
                                                                            25
                                                                  ( xx +
                                                                     1)
                    If a number is in the form x5, its square will be    .
                                       2
                    For example, in (35) , x = 3.                1st part  2nd part
                    To get the first part of the answer, multiply 3 with (3 + 1), i.e., 3 × (3 + 1) = 3 × 4 = 12.
                                     12         25
                    The answer is        .
                                   1st part   2nd part
                           2
                    So, (35)  = 1,225.
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