Page 353 - Start Up Mathematics_8 (Non CCE)
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Alternate Method
                                    Total number of eggs in the box = 20

                                    Number of defective eggs = 8
                                    Let A be the event of taking out a defective egg.
                                           Number of defectiveeggs     8     2
                                    P(A) =                           =    =
                                                  Totaleggs            20    5
                                    \ P (Egg is not defective) =  PA ()  = 1 – P(A)
                                                                   2    3
                                                             = 1 –   =
                                                                   5    5

                    Example 10:     A survey of 150 families shows the following results.
                                    Out of these families one is chosen at   Number of girls in the family  0    1   2
                                    random. What is the probability that the                               30   115  5
                                    chosen family has 2 girls?               Number of families

                    Solution:       Let E be the event of picking a family with 2 girls.
                                    Total number of families = 150
                                    Number of families with 2 girls = 5

                                              Number of families with 2girls   5     1
                                    \ P (E) =                               =     =
                                                 Total numberoffamilies       150   30
                    Example 11:     An urn contains 4 white, 3 black and 5 red marbles. A marble is drawn at random. What is
                                    the probability that it is (a) red?    (b) white?    (c) not black?
                    Solution:       Number of white marbles = 4
                                    Number of black marbles = 3
                                    Number of red marbles = 5
                                    Total number of marbles = 4 + 3 + 5 = 12
                                                          Number of redmarbles      5
                                    (a)  P (Red marble) =                         =
                                                         Total numberofmarbles     12
                                                           Number of white marbles     4     1
                                    (b)  P (White marble) =                         =     =
                                                            Total numberofmarbles     12     3

                                    (c)  P (Not black marble) = 1 – P (Black marble)
                                                                  Number of black marbles
                                                            = 1 –
                                                                  Total numberofmarbles

                                                                  3        1    41-     3
                                                            = 1 –    = 1 –    =       =
                                                                  12       4      4     4

                          EXERCISE

                         1.  Two fair coins are tossed 200 times. Two heads are obtained 120 times. Now, if the coin is tossed
                           at random, what is the probability of getting 2 heads?
                         2.  Two fair coins are tossed simultaneously. Find the probability of getting:
                            (a)  2 tails.      (b)  no head.      (c)  no tail.
                            (d)  same face on each coin.          (e)  different faces on the coins.

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