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10.  A metal pipe is 77 cm long. The inner diameter of a cross-section is 4 cm, the outer diameter being
                           4.8 cm. Find its: (a) inner curved surface area  (b) outer curved surface area    (c) total surface area
                        11.  A cylindrical vessel open at the top has a base diameter of 21 cm and height 14 cm. Find the cost
                                                                               2
                           of tin plating its inner part at the rate of ` 5 per 100 cm .



                                                           MATHS LAB ACTIVITY


                     Objective: To find the formula for lateral surface area of a cylinder
                     Material required: A cylindrical object, coloured paper, pencil, a pair of scissors, scale, glue
                     stick/fevicol
                     Step 1:    Take a coloured sheet of paper and cut a rectangle with
                                width equal to the height of the cylindrical object.
                     Step 2:    Now paste one end of this rectangle on the cylindrical
                                object and wrap it along its curved surface till you
                                reach the starting point.                                                            h
                     Step 3:    Cut off the extra paper. Now remove the rectangular                              r
                                strip from the cylindrical object. You will see that the
                                length of the rectangular strip is the circumference of
                                the base of the cylinder.                           D                               C
                     Now area of rectangle = AB × BC = (2πr) × h = 2πrh
                     Observation: The lateral surface area of a cylinder                                              h
                     is 2πrh.
                     The  above  experiment  can  also  be  done  by  making  a
                      stack of 10–15 one rupee coins.
                                                                                    A               2pr             B
                     A ` 1 coin is circular in shape and its circumference is 2πr.
                     Measure the height of the coins in the stack (h), 2πr + 2πr
                     + 2πr + ... upto the number of coins. The curved surface
                     area will be 2πr × h.



                    Volume of a Cylinder                                                             r

                    Let there be a cylinder with radius r unit and height h unit (Fig. 18.5).
                    Volume of the right circular cylinder = Area of the base × height
                                                                                                  h
                                                           2
                                                      = (pr  × h) cubic units
                                                          2
                                                      =     pr h cubic units                         r
                                                                                                Fig. 18.5
                    Volume of a hollow cylinder                                                                  r
                    Let there be a hollow cylinder with external and internal radii R and r
                    respectively and height h (Fig. 18.6).
                                                                                                                h
                    Volume of the hollow cylinder = External volume – Internal volume
                                                      2
                                                             2
                                                 = (pR h – pr h) cubic units
                                                                                                                R
                                                       2
                                                            2
                                                 =     ph(R  – r ) cubic units                                 Fig. 18.6
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