Page 142 - Start Up Mathematics_8 (Non CCE)
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3x   24
                                    fi    =                                                     (Dividing both sides by 3)
                                        3    3
                                    fi x = 8 is the required solution.

                        EXERCISE 8.3

                        1.  Solve the following linear equations:
                                                                                           2
                                                                                               x
                                 x +1   4                     6x - 8  2                 (2x ++    1 ) (x-  - 12x -  ) 3  7
                                                                                                          )(
                            (a)       =                   (b)       =               (c)                            =
                                2  x +1  3                     5x     3                            x - 2             2
                                3
                                     6x + 11      17           x - 3  3 x - 4           Ê  x + ˆ 2  2  x + 4
                            (d)                  =        (e)       =               (f)   Á   ˜  =
                                ( 2x + 3 -) ( 5x - 2)  2      2 x + 5  6 x + 7          Ë  x + ¯ 1  x + 2
                                                                2
                                3x - ( 8 4x-  )  5             x - 1    3               x    2 (  x 4+ )  2 x  6 x 7+
                            (g)             =             (h)   2    =               (i)   +        =    -
                                      +
                                6x - ( 2 3x)  8                x 3  + 2  10             3      5      15     30
                                x + 3                         x    x 3  x 5                             -7
                            (j)      = 5                  (k)   -    +    =  210     (l)  2(3x – 1) – 5x =    – 2(2x – 7)
                                x - 3                         2   4    6                                2
                        2.  Find a positive value of x which satisfies the given equations:

                                x -  4   - 3                                 x - 15
                                  2
                                                                              2
                           (a)        =                                 (b)         =- 1
                                                                              2
                                3+  x 2  4                                   x - 17
                                                           MATHS LAB ACTIVITY

                                                               Magic Squares
                     In magic squares, the sum of each row, column and diagonal is equal to the magical number for that square.

                     See an example:
                          10  3   8

                           5  7   9          Here numbers 3 to 11 are written in the magical square such that the sum of each
                          6  11  4         row, column and diagonal is a magical number 21.

                     Let’s try another example.

                             2   7

                           8               How can we find the missing numbers?
                                           One way is by trial and error. But there is another systematic way, which is
                             6   5         by using linear equation.

                           x  2  7         Let x be the missing number in row 1, column 1,

                           8                   y be the missing number in row 3, column 1, and
                          y  6   5             m be the magical number.

                     In row 1, x + 2 + 7 = m    fi  x + 9 = m               ...(1)
                     In column 1, x + 8 + y = m                             ...(2)
                     Equating (1) and (2), we get: x + 8 + y = x + 9  fi  8 + y = 9  fi  y = 9 – 8 = 1
                     In row 3,    m = y + 6 + 5 = 1 + 6 + 5 = 12

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