Page 20 - ICSE Math 6

Example 4: Arrange 31,22,567, 34,21,657, 3,43,56,210, 3,44,59,610 and 4,44,02,057 in
descending order.
Solution: 31,22,567 and 34,21,657 are 7-digit numbers. Let’s compare them.

3 1 2 2 5 6 7
3 4 2 1 6 5 7

= 1 < 4
\ 31,22,567 < 34,21,657
3,43,56,210, 3,44,59,610 and 4,44,02,057 are 8-digit numbers in which the leftmost
digits are 3, 3 and 4 respectively.
\ 4,44,02,057 is the greatest among them.

Now, we compare the remaining two numbers 3 4 3 5 6 2 1 0
3 4 4 5 9 6 1 0

= = 3 < 4
\ 3,43,56,210 < 3,44,59,610

Hence, the numbers in descending order are:
4,44,02,057 > 3,44,59,610 > 3,43,56,210 > 34,21,657 > 31,22,567

Example 5: Use place value chart to arrange the following numbers in ascending order.
13,45,678, 43,56,120, 2,35,67,890, 34,52,678 and 1,45,62,187.
Solution: The given numbers when arranged in a place value chart are shown.

Ten Ten
Number Crore Lakh Thousand Hundred Ten One
Lakh Thousand
13,45,678 1 3 4 5 6 7 8

43,56,120 4 3 5 6 1 2 0

2,35,67,890 2 3 5 6 7 8 9 0
34,52,678 3 4 5 2 6 7 8

1,45,62,187 1 4 5 6 2 1 8 7

Step 1: The numbers having minimum number of digits, i.e., seven are 13,45,678,
43,56,120 and 34,52,678. Now their extreme left digits can be arranged as
1 < 3 < 4. Therefore, the three numbers in ascending order are 13,45,678 <
34,52,678 < 43,56,120.
Step 2: Now, we have two numbers having eight digits each, i.e., 2,35,67,890 and
1,45,62,187. Their extreme left digits are unequal and can be arranged as 1 < 2.
Therefore, the numbers in ascending order are 1,45,62,187 < 2,35,67,890.
Step 3: As, every number with less number of digits is smaller than every number
with more number of digits.
Therefore, the given numbers in ascending order are as follows:

13,45,678 < 34,52,678 < 43,56,120 < 1,45,62,187 < 2,35,67,890

4