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12              Operations on Algebraic


                                Expressions







                   Key Concepts

                         • Addition, Subtraction and Multiplication of Algebraic     • Evaluation of Algebraic Expressions by Substituting
                        Expressions                                         a Value for the Variable
                         • Use of Brackets as Grouping Symbols

                    In the previous chapter, we learnt about algebraic expressions. In this chapter, we will learn to apply
                    mathematical operations on algebraic expressions and find their values by substituting the values of
                    the variables.

                    Addition

                    Addition of like terms
                    The sum of two or more like terms is a term whose numerical coefficient is the sum of the numerical
                    coefficients of the given terms. For example,
                    (a)  3a + 6a = (3 + 6)a = 9a                                                    Maths Info

                                  2
                                               2
                          2
                    (b)  5p  + 15p  = (5 + 15)p  = 20p 2
                                                                                              Like terms along with their sum
                                                               + +
                                    5              5        4 6 5       15                form a group of like terms.
                    (c) 2xy + 3xy +  xy  =    2 3     xy =            xy =  xy
                                               ++ 
                                    2              2          2          2
                    Addition of unlike terms
                    Two unlike terms can never be added together to get a single term. So, we just write the unlike terms
                    as the terms of the algebraic expression with an addition sign. For example, the sum of 2ab and 3xy
                    is 2ab + 3xy.

                    Example 1:  Add the following.
                                                                                                        2
                                                                                                           2
                                  (a)  2xy and –13xy               (b)  5pq and 6pq                (c)  3  y  and 3yz
                                                  − 3
                                                                                                           2
                                                                                                                2
                                  (d)  –15pa and     pa            (e)  2ab, –8ab and –7ab         (f)  –3x , –4y , 5x 2
                                                   5
                    Solution:     (a)  2xy + (–13xy) = 2xy – 13xy = (2 – 13)xy = –11xy
                                  (b)  5pq + 6pq = (5 + 6)pq = 11pq

                                             2

                                                2
                                  (c)   Since,  y  and 3yz are unlike terms, they cannot be added to get a single term.
                                             3
                                                  2              2
                                                                    2
                                                     2
                                      \ Sum of  y  and 3yz =  y  + 3yz
                                                  3              3
                                                   –3             3         –75 – 3     –78
                                  (d)  (–15pa) +     pa  =  –15 –       pa =          pa =    pa
                                                         
                                                             
                                                   5              5          5           5
                                  (e)  2ab + (–8ab) + (–7ab) = (2 – 8 – 7)ab = –13ab
                                                    2
                                           2
                                                                        2
                                                           2
                                                                                    2
                                                                              2
                                  (f)  (–3x )  + (–4y ) + 5x = (–3 + 5)x  – 4y  = 2x  – 4y 2
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