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•  To multiply a rational number and an integer, we multiply the numerator of the rational number with
                                                              p       p    r    p × r   p × r
                 the integer, keeping the denominator same, i.e.,   × r =   ×   =  q × 1  =   q  .
                                                              q
                                                                      q
                                                                           1
                                                                    p    r    r   p
               •  Multiplication of rational numbers is commutative, i.e.,   ×   =   ×   .
                                                                              s
                                                                                  q
                                                                    q
                                                                         s
               •  When a rational number is multiplied by 0, the product is always 0, i.e.,
                  p       p    0    p × 0    0
                  q   × 0 =   ×   =  q × 1   =   = 0.
                          q
                                             q
                               1
            Example 14: Find the product:
                               9    –7                  3                       5    2               2    –5
                          (a)    ×                 (b)     × (–9)          (c)     ×            (d)     ×
                               4    5                  11                      11    5               –5    2
                               9    –7    9 × –7   –63                  3            3   –9    3 × –9    –27
            Solution:     (a)    ×      =         =                (b)     × (–9) =     ×    =         =
                               4    5     4 × 5     20                 11           11    1    11 × 1    11
                               5    2    5 × 2    10    2               2    –5   2 × –5    –10
                          (c)     ×   =         =     =            (d)     ×    =         =      = 1
                              11    5    11 × 5   55    11             –5    2    –5 × 2    –10

            Reciprocal of a Rational Number
                                                                                                        p     q
            The reciprocal of a non-zero rational number is its multiplicative inverse, i.e., reciprocal of   is   p  .
                                                                                                        q
                                        3    7                    –5    11      –11
            For example, reciprocal of   is   and reciprocal of      is   , i.e.,
                                        7    3                    11    –5       5


                The product of a non-zero rational number and its reciprocal is always 1.
                             3               –3    –3     8    –3    –8    24
                For example,   ×  reciprocal of    =    ×    =     ×     =     = 1
                             8                8     8    –3     8     3    24

            Division of Rational Numbers
            To divide one rational number by another non-zero rational number, we find the product of the
            first rational number with the reciprocal of the second.
                           3    –2    3                  –2     –3    5    –3 × 5    –15   15
            For example,      ÷    =     ×  reciprocal of     =    ×     =         =     =
                          –4    5    –4                   5     4    –2    4 × –2    –8     8

            Example 15: Find the value of:
                               3   1                         2                   –4
                          (a)    ÷                 (b)  –6 ÷                 (c)     ÷ (–2)
                               4   2                         7                    5
                              –1    3                   –2   1                    2     –7
                          (d)     ÷                (e)     ÷                 (f)     ÷
                               8    4                   13   5                   13     65
                               3   1    3   2   3 × 2    6   3
            Solution:     (a)    ÷   =   ×   =         =   =
                               4   2    4   1   4 × 1    4   2
                                    2   –6    7   –42
                          (b)  –6 ÷   =     ×   =      = –21
                                    7    1    2     2
                              –4           –4    (–2)   –4    1    –4     4    2
                          (c)     ÷ (–2) =     ÷      =    ×     =      =    =
                               5            5     1     5    –2    –10    10   5
                              –1    3   –1    4   –4    –1
                          (d)     ÷   =     ×   =     =
                               8    4    8    3   24    6


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