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Like fractions
                                                                                  1 2 5
            The fractions having same denominators are called like fractions.  ,  ,  , etc. are examples of
                                                                                  7 7 7
            like fractions.

            Unlike fractions
                                                                                      3 3 3
            The fractions having different denominators are called unlike fractions.  ,  ,  , etc. are examples
                                                                                      7 5 11
            of unlike fractions.
            Unit fractions
                                                                            1 1 1 1
            The fractions having 1 as numerator are called unit fractions.  ,  ,  ,  , etc. are examples of unit
                                                                            2 3 5 6
            fractions.
            Example 1:  Solve:

                                                                                     1
                                                                         5
                                                                    2
                                                   3
                          (a)  3 +  7    (b)  5   –        (c)   9   +   +      (d)  7  – 3 5
                                   8         13    8           10   5    2           2     8
                                   7   24    7   24 + 7    31     7
            Solution:     (a)  3 +   =     +   =         =    = 3
                                   8    8    8      8      8      8
                               5    3    40    39     40 – 39     1
                          (b)     –   =      –      =          =
                              13    8   104    104      104      104
                               9    2    5    9    4    25   9 + 4 + 25    38      8     4
                          (c)     +   +   =     +     +    =             =     = 3    = 3
                              10    5    2   10   10    10        10       10     10     5
                                1    5    15   29   60    29   60 – 29    31     7
                          (d)  7  – 3  =     –     =    –    =          =     = 3
                                2    8    2     8    8    8        8       8     8

                                    2 2 9
            Example 2:  Arrange  ,  ,        in descending order.
                                    9  3  21
                          2 2 9
            Solution:       ,  ,
                          9  3  21
                          First convert the given fractions into like fractions. For this we need to find out the
                          LCM of the denominators. LCM of 9, 3 and 21 = 3 × 3 × 7 = 63

                             2    14 2    42       9   27                                          3   9, 3, 21
                          ∴   =     ,   =     and    =
                             9    63 3    63      21   63                                             3, 1, 7
                           42 > 27 > 14

                             42    27   14     2    9    2
                          ∴      >    >     ⇒   >      >
                             63  63  63        3   21    9                                              1
                                                                                                     11   cm
                                                                                                        2
                                                              1                   2
            Example 3:  A rectangular sheet of paper is 11  cm long and 10  cm
                                                                                  3
                                                              2
                                                                                            2
                          wide. Find its perimeter.                                       10   cm
                                                                                            3
            Solution:     Perimeter of rectangular sheet = 2(l + b)
                                                                 1       2          23    32
                                                          = 2 11  + 10   cm = 2         +     cm
                                                                 2       3           2    3
                                                              69 + 64         133          1
                                                          = 2           cm =       cm = 44  cm
                                                                  6            3           3



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