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Example 6:  Solve 5p + 2 = 17 by trial and error method:

            Solution:     5p + 2 = 17
                          (i)  Putting p = 1, LHS = 5(1) + 2 = 7 ≠ 17
                                LHS ≠ RHS, ∴ p = 1 is not the solution.

                          (ii)  Putting p = 2, LHS = 5(2) + 2 = 12 ≠ 17
                                LHS ≠ RHS, ∴ p = 2 is not the solution.
                          (iii) Putting p = 3, LHS = 5(3) + 2 = 17 = RHS

                                LHS = RHS, ∴ p = 3 is the solution.

            Rules for Solving an Equation

            To solve an equation keep in mind the following rules:
            Rule 1:  If we add or subtract the same number on both sides of the equation, it still holds true,
                     i.e., equation is not affected in any way.

            Rule 2:  If we multiply or divide both sides of the equation by the same non-zero number, it still
                     holds true, i.e., the equation is not affected in any way.

            Let’s learn it with an example.
                       2x + 3 = 7                  ⇒ 2x + 3 – 3 = 7 – 3                     ⇒ 2x = 4


               x x                                 x x                                x x



                                                    2x    4
                                                 ⇒      =    ⇒ x = 2
                                                     2    2



                                                     x



            The rules mentioned above are helpful in balancing and solving linear equations.
            Example 7:  Write the step you will use to separate the variable and then solve the equation:

                          (a)  x + 2 = 0        (b)  x – 3 = 0         (c)  x + 3 = 2        (d)  y + 7 = 7

            Solution:  (a) x + 2 = 0                                (b)  x – 3 = 0
                           Subtract 2 from both sides                   Add 3 to both sides

                           ⇒ x + 2 – 2 = 0 – 2                          ⇒ x – 3 + = 0 + 3
                           ⇒ x = –2                                     ⇒ x = 3

                        (c) x + 3 = 2                               (d)  y + 7 = 7

                            Subtract 3 from both sides                  Subtract 7 from both sides
                          ⇒ x + 3 – 3 = 2 + (–3)                        ⇒ y + 7 – 7 = 7 – 7

                          ⇒ x = –1                                      ⇒ y = 0



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