Page 96 - ICSE Math 8
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Example 14:  A group of 30 students went for a holiday and had food provisions for 9 days. After 2 days,
                                  5 more students joined them. How long will the food provisions last?
                    Solution:     If no more students had joined, the food would have lasted for 9 – 2 = 7 more days. Since
                                  5 more students joined, the food will last for lesser days.
                                  Let the remaining food last for x days. Therefore, x will be the fourth term of the proportion
                                  and 7 will be the third term. As x is less than 7, therefore 30 and 35 are the second and first
                                  terms respectively.
                                                   35   7
                                  ∴ 35 : 30 = 7 : x  30  =
                                                        x
                                  ⇒ 35x = 30 × 7  ⇒ x =   7 × 30  = 6
                                                            35
                                  ∴ The remaining food will last for 6 days.

                    Proportional Parts

                    When a given quantity is divided into parts according to a given proportion, the parts obtained are called
                    proportional parts.

                    Example 15:  Divide 324 chocolates among 3 friends in the ratio 7 : 5 : 6.
                                                          7             7
                    Solution:     First friend’s share =   7 + 5 + 6   × 324 =  18  × 324 = 126

                                                             5             5
                                  Second friend’s share =   7 + 5 + 6  × 324 =  18  × 324 = 90
                                                           6             6
                                  Third friend’s share =  7 + 5 + 6  × 324 =  18  × 324 = 108

                                  ∴ The required three shares are 126, 90 and 108 chocolates.

                    Example 16:  Divide 6,250 into three parts in such a way that the first part is 62.5% of the second part and
                                  the ratio between the second and third part is 8 : 12.
                    Solution:     Ratio between the second and third part is 8 : 12.
                                  ∴ If the second part is 8, the third part is 12.
                                                                       62.5 × 8
                                  ⇒ First part = 62.5% of second part =         = 5
                                                                         100
                                  ∴ Ratio between the three parts = 5 : 8 : 12
                                  Let the first, second and third parts be 5x, 8x and 12x.
                                                                6,250
                                  5x + 8x + 12x = 6,250  ⇒ x =        = 250
                                                                 25
                                  ∴ First part = 5x = 5 × 250 = 1,250    Second part = 8x = 8 × 250 = 2,000

                                  Third part = 12x = 12 × 250 = 3,000
                    Example 17:  Rahul has ` 20, ` 50 and ` 100 notes in the ratio 5 : 4 : 7. If the total value of the notes is
                                  ` 10,000, find the number of each kind of notes.
                    Solution:     Let the number of notes be 5x, 4x and 7x.
                                  Value of 5x notes of ` 20 each = ` (5x × 20) = ` 100x
                                  Value of 4x notes of ` 50 each = ` (4x × 50) = ` 200x
                                  Value of 7x notes of ` 100 each = ` (7x × 100) = ` 700x

                                  ⇒ ` (100x + 200x + 700x) = ` 10,000  ⇒ 1,000x = 10,000  ⇒ x = 10
                                  ∴ Number of ` 20 notes = 5x = 50
                                  Number of ` 50 notes = 4x = 40   Number of ` 700 notes = 7x = 70

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