Page 235 - ICSE Math 7
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Example 1:  A rectangular plot is 50 m long and 30 m wide. Find the:
                                                                                            2
                                  (a)  area of the plot.          (b) cost of the plot, if 1 m  costs ` 1,000.
                    Solution:     (a)  Area of rectangle = length × breadth
                                      Length of the rectangular plot = 50 m
                                      Breadth of the rectangular plot = 30 m
                                                                                           2
                                      ∴ area of rectangular plot = 50 m × 30 m = 1,500 m .
                                                                             2
                                  (b)  Cost of rectangular plot = Cost of 1 m  of the plot × area of the plot
                                                               =     ` 1,000 × 1,500 = ` 15,00,000
                                      ∴ cost of plot is ` 15,00,000.
                    Example 2:  The perimeter of a rectangular sheet is 100 cm. If its
                                  length is 40 cm, find its breadth. Also find the area of     Try These
                                  the rectangle.                                              1.   Find the area of a square
                    Solution:       Perimeter of rectangular sheet  = 100 cm                     park  whose  perimeter  is
                                                                                                 220 m.
                                            Length (l) of the sheet  = 40 cm                  2.    Find the breadth of a
                                              Perimeter = 2(l + b)  = 100 cm                     rectangular plot of land, if
                                                                                                               2
                                                      ⇒ 2(40 + b)  = 100                         its area is 180 m  and the
                                                         ⇒ 40 + b  = 50                          length is 20 m. Also find its
                                                                                                 perimeter.
                                                              ⇒ b  = 10 cm
                                                 Area of the sheet  =  l × b = 40 cm × 10 cm = 400 cm  2

                    Example 3:  The area of a square park is same as that of a rectangular park. If the side of the square
                                  park is 80 m and the length of the rectangular park is 100 m, find the breadth of the
                                  rectangular park.

                    Solution:                 Side of the square park  = 80 m
                                                                                         2
                                                                              2
                                              Area of the square park  = (side)  = (80 m)  = 6,400 m 2
                                   Since, area of the rectangular park  = area of the square park
                                                              ⇒ l × b  = 6,400 m 2
                                                          ⇒ 100 × b  = 6,400              ( l = 100 m)
                                                                                                 2
                                            ∴ breadth (b) of the park  = area ÷ length = 6,400 m  ÷ 100 m = 64 m
                    Example 4:  A wire is in the shape of a rectangle. Its length is 40 cm and breadth is 20 cm. If the
                                  same wire is re-bent to form a square, what will be the measure of its side? Also find
                                  which shape will enclose more area, and by how much?

                    Solution:           Length of the rectangle = 40 cm
                                       Breadth of the rectangle = 20 cm
                                          Perimeter of the wire = 2 × (l + b) = 2 × (40 + 20) cm = 2 × 60 cm = 120 cm
                                        Perimeter of the square = 4 × side = 120 cm
                                                                  120
                                              ∴ side of square =    4   cm = 30 cm

                                                                        2
                                                Area of square = (side)  = 30 cm × 30 cm = 900 cm    2
                                              Area of rectangle = l × b = 40 cm × 20 cm = 800 cm   2
                                                              2
                                                                         2
                                  Difference in area = 900 cm  – 800 cm  = 100 cm    2
                                  Thus, the square shape encloses more area.

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