Page 233 - ICSE Math 7
P. 233

6.  Construct a ∆ ABC in which AB = 6 cm, AC = 6.5 cm and ∠BAC = 60º.
                      7.  Construct a ∆ PQR in which PQ = 5.2 cm, PR = 6.0 cm and ∠QPR = 45º.
                      8.  Construct a triangle ABC in which AB = 6.2 cm and ∠A = ∠B = 75º.
                      9.  Construct a triangle ABC in which BC = 6.5 cm, ∠C = 45º and ∠B = 60º.
                     10.  Construct a right-angled triangle having hypotenuse 7 cm and one of its acute angles measuring 45º.

                        Maths Lab Activity

                     Objective:  Construction  of an equilateral triangle  by
                                  paper folding



                     Step 1:    Take a rectangular paper with base AB.

                                                                                              A            B

                     Step 2:    Fold the paper vertically into 2 halves to obtain
                                the perpendicular bisector through the midpoint
                                D of the width AB. Press to form the crease and
                                then unfold it.


                                                                                                   A     D      B
                     Step 3:    Next, make a fold so that the corner point B

                                falls on the perpendicular bisector. Press it when
                                the fold passes through A.                                 B
                                                                                                 E

                     Step 4:    Make another fold along AB (as shown) so that
                                the vertical length along A coincides with AE.        A                 A

                                Press it to form a crease.


                     Step 5:    Unfold the paper and mark the point C as shown.         C                 C



                     Step 6:    Finally, either fold or join  BC to obtain an
                                equilateral ∆ ABC.                                 A     D      B    A     D      B

                     Justification:

                     Can you justify why ∆ ABC is equilateral?
                     [Hint:     Since AB coincides with AC (as B lies on C),

                                ∴   AB = AC and D ADC ≅ D BDC (why?)

                                Hence, AC = BC.]









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