Page 161 - ICSE Math 7
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Example 5:  Solve the inequation 4(x – 5) > 3x – 25, x ∈{–4, –5, 0, 4} and represent the solution
                                  set graphically.

                    Solution:     4(x – 5) > 3x – 25
                                  ⇒ 4x – 20 > 3x – 25

                                  ⇒ 4x – 3x > –25 + 20

                                  ⇒ x > –5
                                  So, the possible values of x from the replacement set are –4, 0 and 4.

                                  \ Solution set = {–4, 0, 4}
                                  To represent the solution set graphically, draw a number line and mark –4, 0 and 4 by
                                  thick dots.


                                                   –5  –4  –3  –2  –1  0   1  2   3   4

                    Example 6:  If a labour earns ` 800 per day, how many labourers can work within a monthly budget
                                  of ` 1,44,000?
                    Solution:     Let the number of labourers be x.

                                  Then, wages earned by x labourers per day  = ` 800 x
                                  Wages that x labourers will earn per month = ` (800 x × 30) = ` 24,000 x
                                  But, as per the given condition this amount cannot exceed ` 1,44,000.
                                  Therefore, 24,000 x ≤ 1,44,000
                                  24,000 x    1,44,000
                                            ≤
                                   24,000      24,000
                                  x ≤ 6
                                  Hence up to 6 labourers can work in a monthly budget of ` 1,44,000.


                                                                EXERCISE


                      1.  Solve the following inequations.

                        (a)  x + 4 > 2, x ∈ Z           (b)  3x + 3 < 12, x ∈ N        (c)  3(x + 2) ≤ 24 + x, x ∈ W
                                                                                            x        x
                        (d)  2x + 9 ≥ 3x – 5, x ∈ {10, 11, 12, 13, 14, 15}             (e)     – 1 ≥   – 2, x ∈ W
                                                                                            3       2
                      2.  Find the solution set of the following, if the replacement set is {0, 1, 2, 3, 4, 5}.

                        (a)  3 – 2x < 6                 (b)  x + 2 ≤ 5                 (c)  5(x + 7) ≥ 35 – x

                             5x – 1                          2x   1     x    1
                        (d)         ≥ 3                 (e)     –   ≥      +           (f)  6(2 – x) ≥ 4(x – 8)
                               3                             3    4     5    2
                      3.  Solve the following inequations and represent the solution set graphically.
                        (a)  x + 6 > 12, x ∈ Z                     (b)  13x – 19 ≥ 7, x ∈ N

                        (c)  8x + 1 ≤ 4x + 5, x ∈ W                (d)  7(x + 1) < 5x + 10, x ∈ W
                      4.  Ria needs at least 5 packets of pencils having 15 pencils each. If one pencil costs ` 8 and Ria has
                        only ` 600, how many packets of pencils can she buy?


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