Page 84 - ICSE Math 6
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1    5    1     3
                                  RHS = 5 ×2 +       5 ×2
                                            4    6    4     4
                                           5×4 1 2×6 5+   +    5×4 1 2×4 3+   +
                                        =          ×         +         ×
                                              4         6          4         4
                                           21 17    21 11     7  21 ×17   21×11 119      231
                                        =    ×    +    ×    =          +         =     +
                                           4    6    4    4    4× 6  2    4×4       8    16
                                          119×2 231+      238 231+     469       5
                                        =               =           =      = 29
                                                16            16       16       16

                                  \ LHS = RHS

                                             1    1                  1     
                    Example 27: Simplify 3 of       +  4 ÷    4× 4– 4 –        .
                                                              
                                                                   
                                             3    2                  5     
                                                                             +
                                    1    1                  1       3×3 1     1               4×5 1   −    
                    Solution:     3 of     +  4 ÷    4× 4– 4 –         =    of    + 4 ÷  4× 4 –             
                                                                                               
                                                     
                                                          
                                    3    2                  5        3        2                 5        
                                                                        10    1              19 
                                                                     =     of   + 4 ÷    4× 4 –
                                                                                          { }
                                                                        3     2               5 
                                                                        10    1          { 4×5 19   −
                                                                     =     of   +  4 ÷    4×        }
                                                                         3    2               5      
                                                                        10    1          1   10    1       4
                                                                     =     of   + 4 ÷    4×    =  of  +  4 ÷
                                                                        3     2          5    3    2       5

                                                                       10 5   1        4    5       4
                                                                     =      ×    + 4 ÷   =   + 4 ÷
                                                                        3     2  1     5    3       5

                                                                       5     1  5     5
                                                                     =  + 4 ×       =   + 5
                                                                       3        4 1   3
                                                                       5 + 5 × 3    20     2
                                                                     =            =    = 6
                                                                           3        3      3
                    Word Problems

                                              2
                    Example 28: In a class,      of the students are boys. If the total number of students is 66, then find
                                             11
                                  the number of boys and girls in the class.
                                              2
                    Solution:     Given that     of the students are boys.
                                             11
                                                                         2           2          2× 66  6
                                  So, the number of boys in the class =     of 66 =     × 66 =           = 12
                                                                         11         11            11 1
                                  Thus, there are 12 boys in the class.

                                  Total number of students = 66
                                  Number of boys = 12

                                  \ Number of girls = 66 – 12 = 54


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