Page 83 - ICSE Math 6
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                      8.  If   of a number is 27, then find the number.
                           5
                            2    x            y
                      9.  If   =  , then find   .
                           15    y            x

                     10.  Find the reciprocal of the following.
                             4                       2                        1                       1
                        (a)                     (b)                     (c) 3                   (d) 5
                             9                       17                       2                       7
                    Combination of Fundamental Operations

                    When two or more operations are used in an expression, then we simplify the expression by first
                    operating the fractions inside the bracket, then the operation ‘of’ followed by division, multiplication,
                    addition and subtraction.
                    Thus, for simplification we follow BODMAS. It stands for:

                             B               O               D               M               A               S
                             ↓               ↓               ↓               ↓               ↓               ↓
                          Bracket           Of           Division      Multiplication    Addition       Subtraction
                                            4    10   9      2  3 
                    Example 25: Simplify      of    ÷    +    +    .
                                            5    11 11     3   4 

                                   4   10    9     2  3     4    10   9     2×4 3×3+  
                    Solution:        of    ÷   +    +     =   of    ÷    +            
                                   5    11 11     3   4     5    11 11         12     
                                                              4   10    9   17    4 10    9    17
                                                           =    of    ÷   +    =   ×    ÷    +
                                                              5    11 11 12       5 11 11 12

                                                              8    9     7    8    11    17
                                                           =     ÷    +     =    ×     +
                                                             11    11   12    11    9    12
                                                             8   17    8 × 4 + 17 × 3
                                                           =  +      =
                                                             9   12          36
                                                             32 51+    83     11
                                                           =         =     = 2
                                                                36     36     36
                                               1    5     3     1    5    1     3
                    Example 26: Prove that 5 × 2 +      2     =  5 ×2 +  5×2 .
                                               4    6     4     4    6     4    4

                                            1    5     3 
                    Solution:     LHS = 5 ×2 +        2  
                                               
                                            4    6     4 
                                                           +
                                          5×4 1   +  2×6 5     2×4 3   +
                                        =         ×          +          
                                             4          6          4    
                                          21   17 11      21   17×2 11×3+   
                                        =    ×    +      =  ×               
                                           4     6   4    4         12      

                                                   +
                                          21   34 33      21   67   7  21 ×67   469       5
                                        =    ×           =  ×       =         =      = 29
                                           4      12      4     12   4× 12  4    16      16

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