Page 150 - ICSE Math 6
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–3
                                      Verification: Substitute x =     in LHS
                                                                    2

                                      4(x + 2) =  4     –3  +2 =      4   –3+ 4     =  4     1     =  2
                                                     2           2         2 
                                                     –3
                                      Substitute x =     in RHS
                                                      2
                                                    –3 
                                       2x + 5 =  2       + 5 = –3 + 5 = 2
                                                    2 

                                      As LHS = RHS, therefore the solution x =    –3  is correct.
                                                                                   2
                                       y        1
                                  (c)    +1 2=
                                       7        7
                                          y      15
                                      ⇒     +1=
                                          7       7
                                      ⇒   y  =  15  − 1                           (Transposing 1 to the other side)
                                          7    7
                                          y   15 7−    8
                                      ⇒     =        =
                                          7      7     7
                                          y       8
                                      ⇒     × 7 =   × 7                           (Multiplying both sides by 7)
                                          7       7
                                      ⇒ y = 8

                                      Verification:  Substitute y = 8 in LHS
                                        y       8      8 + 7   15     1
                                          + 1 =   +1=        =    =  2 = RHS
                                        7       7        7     7      7
                                      As LHS = RHS, therefore the solution y = 8 is correct.


                                                             EXERCISE 13.1

                      1.  Express each of the following statements in algebraic form.
                         (a)  A number when increased by 21 gives 30.
                        (b)  Twice of a number when decreased by 9 gives 11.
                         (c)  x subtracted from 10 equals 3.
                        (d)  18 divided by x is equal to 6.
                         (e)  One-fourth of a number when added to two-sevenths of the same number gives 135.
                         (f)  The sum of two consecutive numbers is 21.
                      2.  Write suitable statements for the following algebraic expressions.


                        (a)  15 – x = 6         (b)  4x – 4 = 76        (c)  a + 3 = 5          (d)  3a + 9 = 15
                                                     10
                        (e)  7 – a = 2           (f)   x   = 1          (g)  y + 5 = 10         (h)  3z – 10 = 2
                      3.  Solve.
                                                                                         x        1
                         (a)  2a + 6 = 8              (b)  x – 3 = 15               (c)    +2 3=
                                                                                         7        2
                              y                                 x                        5z
                        (d)    +5 5=                  (e)  10 −   =  30             (f)     = 10
                             5                                  3                        20

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