Page 120 - ICSE Math 6
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Alternatively, number of red pens = (100 – 40)% of 110 = 60% of 110
                                                                        60
                                                                     =      × 110 = 66
                                                                       100

                    Example 3:  A man spends 20% of his salary on shopping and 25% on food. How much money does
                                  he save if his salary is ` 50,000?
                    Solution:     Money spent on shopping  = 20% of ` 50,000

                                                                   20         
                                                              = `    ×50,000  = ` 10,000
                                                                               
                                                                   100        
                                  Money spent on food  = 25% of ` 50,000

                                                              25          
                                                         = `     ×50,000  = ` 12,500
                                                                           
                                                              100         
                                  Money saved = ` 50,000 – ` 10,000 – ` 12,500 = ` 27,500

                                  Alternatively, money saved = (100 – 20 – 25)% of ` 50,000
                                                               = 55% of ` 50,000
                                                                    55          
                                                                                 
                                                               = `     ×50,000  = ` 27,500
                                                                    100         
                    Example 4:  Out of 60 students in a class, 25% students got the first division in the annual examination,
                                  45% students got the second division and the remaining students just passed. Find the
                                  number of students who just passed.
                                                                                                 25
                    Solution:     Number of students who got the first division = 25% of 60 =        ×60  = 15
                                                                                                100
                                                                                                    45
                                  Number of students who got the second division = 45% of 60 =         ×60  = 27
                                                                                                   100
                                  \ Number of students who just passed = (60 – 15 – 27) = 18
                                  Alternatively, number of students who just passed = (100 – 25 – 45)% of 60

                                                                                                     30
                                                                                     = 30% of 60 =       ×60  = 18
                                                                                                     100
                    Finding the Number from its Given Percentage
                    Write the given percentage as a fraction with the denominator 100 and then divide the given number
                    by this fraction to get the required number.

                    Example 5:  If 25% of a number is 25, find the number.

                                                              25    25 ×100
                    Solution:     Required number =  25 ÷          =          = 100
                                                              100      25
                                       1
                    Example 6:  If 13 %  of a number is 54, find the number.
                                       2
                                           1       27         27
                    Solution:     Since 13 %  =       % =
                                           2       2       2 × 100


                                  \ Required number =  54 ÷       27       =   54×2×100   = 400
                                                                2×100         27


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