Page 43 - ICSE Math 8
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Addition of two consecutive triangular numbers forms a square number.






                                          1 + 3 = 4 = 2 2      3 + 6 = 9 = 3 2      6 + 10 = 16 = 4 2
                                                                       2
                                                                                    2
                      II.  In between  two consecutive  square numbers  n  and (n + 1) , there  exists ‘2n’ non-perfect  square
                          numbers.
                             Consecutive         Non-perfect square numbers between            Number of non-perfect
                           square numbers           two consecutive square numbers                square numbers
                            2
                           1 , 2 2            2, 3                                           2 = 2 × 1
                            2
                           2 , 3 2            5, 6, 7, 8                                     4 = 2 × 2
                            2
                           3 , 4 2            10, 11, 12, 13, 14, 15                         6 = 2 × 3
                                                                                           
                            2
                                               2
                                                      2
                                                                      2
                                                             2
                           n , (n + 1) 2      n  + 1, n  + 2, n  + 3, ..., n  + 2n           2n = 2 × n
                      III.  Squares of natural numbers having all digits as 9 follow the given pattern.
                                  Number                   Squares                            Pattern
                                                    2
                                     9             9  = 81                   8 + 1 = 9 = 9 × 1
                                                      2
                                     99            99  = 9801                9 + 8 + 0 + 1 = 18 = 9 × 2
                                                       2
                                    999            999  = 998001             9 + 9 + 8 + 0 + 0 + 1 = 27 = 9 × 3
                                                        2
                                    9999           9999  = 99980001          9 + 9 + 9 + 8 + 0 + 0 + 0 + 1 = 36 = 9 × 4
                                                                                                

                      IV.  If two consecutive odd natural numbers are multiplied and 1 is added to the product, it is equal to the
                          square of the even number between them, i.e., {(2n – 1) × (2n + 1)} + 1 = (2n) 2

                                                      2
                                                                                  2
                          For example, 1 × 3 + 1 = 4 = 2         3 × 5 + 1 = 16 = 4         5 × 7 + 1 = 36 = 6 2
                      V.  If two consecutive even natural numbers are multiplied and 1 is added to the product, it is equal to the
                          square of the odd number between them, i.e., {(2n) × (2n + 2)} + 1 = (2n – 1) 2
                                                      2
                                                                             2
                          For example, 2 × 4 + 1 = 9 = 3     4 × 6 + 1 = 25 = 5     6 × 8 + 1 = 49 = 7 2
                      VI.  The square of any odd natural number other than 1 can be represented as a sum of 2 consecutive natural
                                              2
                                                                                                            2
                                                    2
                                                                                                       2
                                                                                                                2
                          numbers, i.e., (2n + 1)  = 4n  + 4n + 1                            {Q (a + b)  = a  + b  + 2ab}
                                      2
                                                                            2
                                                                2
                                            2
                                  = 2n  + 2n  + 2n + 2n + 1 = (2n  + 2n) + (2n  + 2n + 1)
                                                              2
                                        2
                                                                                        2
                          For example, 3  = 9 = 4 + 5        5  = 25 = 12 + 13        7  = 49 = 24 + 25
                      VII.  The natural numbers containing all digits as 6 with units digit as 7 follow another interesting pattern.
                                                            2
                                                           7   =  49
                                                            2
                                                         67   =  4489
                                                            2
                                                        667   =  444889
                                                            2
                                                       6667   =  44448889    and so on.
                    Example 4:    Which of the following natural numbers are not perfect squares? Give reasons.
                                  (a)  2,037    (b)  1,024    (c)  5,298    (d)  33,222    (e)  13,456
                    Solution:     (a), (c) and  (d) are not perfect squares because numbers ending with digits 2, 3, 7, 8 are never
                                  perfect squares.
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