Page 270 - ICSE Math 8
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Example 3:    Two fair dice are rolled simultaneously. Find the probability of getting:
                                  (a)  an odd number as the sum.
                                  (b)  a doublet (i.e., same number on both dice).

                                  (c)  a multiple of 2 on one die and a multiple of 3 on the other.
                                  (d)  a total of at least 11.
                                                                                                    2
                    Solution:     Total number of outcomes when two dice are rolled simultaneously = 6  = 36
                                  (a)  Let A be the event of getting the sum as an odd number, i.e., 3, 5, 7, 9 and 11.
                                        The outcomes favourable to event A are (1, 2), (2, 1), (1, 4), (2, 3), (3, 2), (4, 1), (1, 6), (2, 5),
                                      (3, 4), (4, 3), (5, 2), (6, 1), (3, 6), (4, 5), (5, 4), (6, 3), (5, 6) and (6, 5).
                                      \ Favourable outcomes =18
                                                     Favourable outcomes   18    1
                                      Hence, P(A) =                      =    =
                                                       Total outcomes      36    2

                                  (b)  Let B be the event of getting a doublet.
                                      The outcomes favourable to B are (1, 1), (2, 2), (3, 3), (4, 4), (5, 5) and (6, 6).
                                      \ Favourable outcomes = 6
                                                     Favourable outcomes   6    1
                                      Hence, P(B) =                      =    =
                                                       Total outcomes      36   6
                                  (c)   Let D be the event of getting a multiple of 2 on one die and a multiple of 3 on the other.
                                        The outcomes favourable to event D are (2, 3), (2, 6), (4, 3), (4, 6), (6, 3), (6, 6), (3, 2),
                                      (3, 4), (3, 6), (6, 2) and (6, 4).
                                      \ Favourable outcomes = 11

                                                     Favourable outcomes    11
                                      Hence, P(D) =                       =
                                                        Total outcomes      36
                                  (d)  Let E be the event of getting a total of at least 11, i.e., 11 and 12.
                                      The outcomes favourable to event E are (5, 6), (6, 5) and (6, 6).

                                      \ Favourable outcomes = 3
                                                     Favourable outcomes   3    1
                                      Hence, P(E) =                      =    =
                                                       Total outcomes      36   12

                    Example 4:    A card is drawn from a well-shuffled deck of 52 cards. Find the probability of
                                  (a)  getting a club card.     (b)  getting a red card.   (c)  getting a black queen.
                    Solution:     A deck of playing cards has 52 cards.
                                  \ Total number of outcomes = 52

                                  (a)  Let A be the event of getting a club card. There are 13 club cards.
                                      \ Favourable outcomes = 13
                                                       Favourable outcomes      13   1
                                      Hence, P(A) =                           =    =
                                                     Total numberof outcomes    52   4
                                  (b)  Let B be the event of getting a red card. There are 26 red cards in a deck of playing cards.

                                      \ Favourable outcomes = 26
                                                     Favourable outcomes   26   1
                                      Hence, P(B) =                      =    =
                                                       Total outcomes      52   2


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