Page 98 - ICSE Math 7
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72    x
                                                                            2
                                  ⇒   x   =     ⇒ x × x = 72 × 8    ⇒ x  = 72 × 8
                                           8
                                                      2
                                  ⇒ x = 576    ⇒ x  = 24 × 24    ⇒ x = 24
                                  So, 24 is the mean proportional between 72 and 8.
                    Example 15: Find the third proportional to 12 and 24.
                    Solution:     Let the third proportional be x.

                                  ∴ 12, 24 and x are in continued proportion.
                                     12    24
                                  ⇒      =      ⇒ 12 × x = 24 × 24
                                     24    x
                                         24 × 24
                                  ⇒ x =           = 48
                                            12
                                  So, 48 is the third proportional to 12 and 24.

                    Example 16: If x : y = 3 : 2 and y : z = 5 : 4, find x : y : z.
                                                 3   2   3
                    Solution:     x : y  = 3 : 2 =   :   =   : 1
                                                 2   2   2
                                  Similarly,  y : z = 5 : 4
                                                        4
                                                    5
                                                  =   :   = 1 :  4
                                                        5
                                                    5
                                                                5
                                                   3      4
                                  Thus,   x : y : z =   : 1 :
                                                   2      5
                                                     3                  4    
                                                                ×
                                                 =    2  × 10 :  ( 110) :    5  × 10      (LCM of 2 and 5 = 10)
                                                          
                                                                                
                                                                        
                                                   
                                                                                
                                                          
                                                = 15 : 10 : 8
                    Example 17: Rohit has three bags. The first bag weighs 2 kg 500 g and the third bag weighs 10 kg.
                                  Find the weight of the second bag if its weight is mean proportional between the weights
                                  of the other two bags.
                    Solution:     Let the weight of the second bag be x kg.
                                                                       500         1       5
                                  Weight of first bag = 2 kg 500 g = 2 1000  kg = 2  kg =   kg
                                                                                   2
                                                                                           2
                                      5
                                  So,  kg, x kg and 10 kg are in continued proportion.
                                      2
                                     5    1    x              5
                                                          2
                                  ⇒   ×   =         ⇒ x  =   × 10 = 25
                                     2    x   10              2
                                      2
                                  ⇒ x  = 5 × 5    ⇒ x = 5
                                  ∴ Weight of the second bag is 5 kg.

                                                              EXERCISE 7.2

                      1.  Find x such that:
                         (a)  x : 7 = 12 : 84     (b)  102 kg : x :: 34 m : 110 m  (c)  x : 12 :: 12 : 7
                                                                                          1    1
                        (d)  0.8 : 2.4 :: x : 7.5   (e)  28 g : 140 g :: 17 kg : x   (f)  4  : 3  = x : 20
                                                                                          3
                                                                                               3
                      2.  Find the fourth proportional to the following.
                                                  1                                1   1    5         1 1 1
                        (a)  2, 5, 4    (b)  6, 4,      (c)  1.4, 1.6, 3.5    (d)  2 , 1 , 1    (e)  ,  ,
                                                  2                                3   2    9         3 2 6


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