Page 85 - ICSE Math 7
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Example 5:  Identify the empty set, singleton set and pair set.
                                  (a)  X = {x | x + 5 = 4, x ∈ N}            (b)  Y = {y | 2y + 5 = 11, y ∈ N}
                                                2
                                  (c)  A = {x | x = 9, x ∈ Z}

                    Solution:     (a)  x + 5 = 4 ⇒ x = 4 – 5 = –1
                                      \ There is no natural number which satisfies x + 5 = 4. So, X = f ⇒ n(X) = 0.
                                      Thus, X is an empty set.
                                                                         6
                                  (b)  2y + 5 = 11 ⇒ 2y = 11 – 5 ⇒ y =   = 3              Try This
                                                                         2
                                      \ Y = {3} ⇒ n(Y) = 1
                                      Thus, Y is a singleton set.                        Identify the disjoint and overlapping
                                                                                         pairs of sets.
                                       2
                                  (c)  x = 9, x ∈ Z                                      (a)  A = {4, 8, 12, 16, 20} and

                                      ⇒ x = 3, –3                                           B = {1, 2, 4, 5, 10, 20}
                                                                                         (b)  X = {a | a is a prime number} and
                                      \ A = {3, –3} ⇒ n(A) = 2                              Y = {b | b is an even number}
                                      Thus, A is a pair set.                             (c)  P = {1, 3, 5, 7, 11, 15} and
                                                                                            Q = {0, 2, 4, 6, 8, 10}
                    Subsets
                    If two sets, X and Y, are such that every member of X is also a member of Y, then X is a subset of Y
                    and it is denoted by X ⊆ Y (read as X is a subset of Y). It can also be said that Y is a superset of X
                    and  is denoted by Y ⊇ X. If all the elements of X are in set Y and there exists at least one member of
                    Y which is not in X, then X is known as a proper subset of Y and is denoted by X ⊂ Y.

                    Points to remember

                    •  Every set is a subset of itself, i.e., A ⊆ A.                                Maths Info
                    •  Every proper subset is a subset but converse is not always true.       The empty set f is a subset of
                    •  X ⊆ Y ⇒ either X ⊂ Y or X = Y                                          every set.
                    •  If X ⊆ Y and Y ⊆ X, then X = Y
                    •  If X ⊆ Y and Y ⊆ Z, then X ⊆ Z
                    •  If X ⊆ f, then X = f
                    •  All the subsets except the set itself are proper subsets of a set.


                    Number of subsets
                                                                       n
                                                        n
                    If a set has n elements, then it has 2  subsets and 2 – 1 proper subsets.

                    For example, if X = {a, b}, then all possible subsets of X are f, {a}, {b} and {a, b}. So, there are
                                                                                                       2
                     2
                    2  = 4 possible subsets. Also, proper subsets of X are f, {a} and {b} which are 3 (2  – 1) in number.
                    Universal Set

                    Universal set is a set which contains all the given sets as its subsets
                    or (under consideration). It is denoted by U or ξ (read pxi). Except
                    the elements of the given sets, universal set may have extra elements           Maths Info
                    also.
                    For example, if A = {2, 4, 6, 8, 10} and B = {1, 3, 5, 6}, then the       Universal set for the sets under
                    set {1, 2, 3, 4, 5, 6, 8, 10} is the universal set for sets A and B.      consideration is not unique.
                    In this case, we can also take N, the set of natural numbers as the
                    universal set.


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