Page 74 - ICSE Math 7
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3 2
                                                                 2
                                                             16a (b )
                                                        =
                                                                2 3
                                                                      2 3
                                                           512(a ) (b )
                                                               2 6
                                                           16a b
                                                                                       m n
                                                        =                     [Using (a )  = a m×n ]
                                                                6 6
                                                           512a b
                                                             1                       a m     1  
                                                        =                      Using      =
                                                                                               −
                                                           32a 6–2                   a n  a n m 
                                                                                                 
                                                            1
                                                        =
                                                           32a 4
                                                                          −
                                                                          4
                                                          1  − 3      3     1
                                                                    0
                                        2 0
                                               –4
                                                     –6
                                  (c)  (3 )  + 3  ÷ 3  +     = 3 +         +
                                                                          6 
                                                           3          3    3 − 3
                                                                       
                                                                          −
                                                                = 1 + (3 –4–(–6) ) + 3 3
                                                                                       0     a m    mn       1      m 
                                                                                                      −
                                                                                Using a = 1,  n  =  a   and  − m  =  a  
                                                                                             a              a         
                                                                = 1 + (3 –4+6 ) + 27
                                                                        2
                                                                = 1 + 3  + 27
                                                                = 1 + 9 + 27 = 37
                                         5  2  4      − 3  2  125     25 4    9  125 
                                                                                 ÷
                                  (d)      ×  ÷       ×      =   64  ×    25  ×   
                                                 
                                           8   5       5   81      5        81 
                                                                  
                                                                         5    5    5    9    9
                                                                    =       ÷    =    ×   =
                                                                        16   9    16    5   16
                                                              EXERCISE 5.2
                                                  –3
                      1.  By what number should 2  be multiplied so that the product is 16?
                                                    –1
                                                                                             –1
                      2.  By what number should (3)  be multiplied so that the product is (6) ?
                                                     –1
                                                                                              –1
                      3.  By what number should (–9)  be divided so that the quotient is (18) ?
                      4.  Using the laws of exponents, simplify and write the answer in exponential form.
                                                                     11
                                                                           7
                                                                                3
                                 5
                                                1
                                         2
                         (a)  (–3)  × (–3)  × (–3)             (b)  (6  × 6  × 6 ) ÷ 6 5
                               2 3
                                                                                   –3 2
                                                                        2 3
                                     5
                         (c)  (3 )  ÷ 3                        (d)  {(–5) }  × {(–5) }
                      5.  State true or false and justify your answer:
                                                                                                                0
                                                                                   3
                                                                              3
                                                                                                           0
                                                                                          3
                                                     3
                                        3
                                  3
                                                          2
                        (a)  3 × 5  = 15        (b)  2  > 3              (c)  5  × 6  = 30            (d)  3  × 2  = 5 0
                      6.  Simplify each of the following:
                                   3
                                                                                                                2
                                                                                                           9
                                                                               3
                                                                                    2
                             49 × 7  × 100          121 × 5 3                 a ×  b × b ×  a 2           2  × 4  × 5 3
                                                                                         3
                         (a)                    (b)                      (c)                          (d)
                                3
                                    3
                                                       2
                             10  × 3  × 7 2          11  × 5                       a ×  b                   16 × 10 2
                                                                                    2
                      7.  Using laws of exponents, compute each of the following and answer in exponential form.
                                  3
                                   
                                 6   4             5   6              – 1  7  9                    – 3  5  5
                                                          3
                                                           
                         (a)                (b)                  (c) ( c  3  m 2              (d) ( c    m 2
                                   
                                 7                 9                                                5
                                                           
                 60
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