Page 69 - ICSE Math 7
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Example 3:  Express each of the following numbers using exponential notation.
                                                                                        –8             64
                                  (a)  1,024        (b)  243       (c)  15,625     (d)            (e)
                                                                                        343            729
                    Solution:     (a)  1,024 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 = 2 10

                                  (b)  243 = 3 × 3 × 3 × 3 × 3 = 3 5
                                  (c)  15,625 = 5 × 5 × 5 × 5 × 5 × 5 = 5 6

                                       –8    (–2) × (–2) × (–2)    –2  3
                                  (d)      =                    =
                                      343        7 × 7 × 7         7
                                       64    2 × 2 × 2 × 2 × 2 × 2     2  6
                                  (e)      =                        =
                                      729    3 × 3 × 3 × 3 × 3 × 3     3
                    Example 4:  Identify the greater number, wherever possible, in each of the following.
                                       3
                                                                   2
                                                                                     2
                                                             8
                                             7
                                  (a)  7  or 3          (b)  2  or 8         (c)  100  or 2 100
                                       3
                    Solution:     (a)  7  or 3 7
                                                                 7
                                       3
                                      7  = 7 × 7 × 7 = 343 and 3  = 3 × 3 × 3 × 3 × 3 × 3 × 3 = 2,187
                                          3
                                      ∴ 7  < 3 7
                                       8
                                             2
                                  (b)  2  or 8
                                                                                     2
                                       8
                                      2  = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 = 256 and 8  = 8 × 8 = 64
                                          8
                                      ∴ 2  > 8 2
                                          2
                                  (c)  100  or 2 100
                                          2
                                      100  = 100 × 100 = 10,000
                                      and 2 100  is a very large number
                                             2
                                      ∴ 100  < 2  100
                    Example 5:  Express each of the following as a product of powers of their prime factors.
                                  (a)  216              (b)  1,080           (c)  3,600
                                                                      3
                    Solution:     (a)  216 = 2 × 2 × 2 × 3 × 3 × 3 = 2  × 3 3
                                                                            3
                                                                                 3
                                  (b)  1,080 = 2 × 2 × 2 × 3 × 3 × 3 × 5 = 2  × 3  × 5
                                                                                                             2
                                                                                                        4
                                  (c)  3,600 = 2 × 2 × 5 × 5 × 6 × 6 = 2 × 2 × 2 × 2 × 3 × 3 × 5 × 5 = 2  × 3  × 5 2
                                                                        4
                                                       4
                                                                                          3
                    Example 6:  Simplify:  (a) 2 × 10          (b) 0 × 7             (c) 3  × 10 4
                                                     4
                                             (d) (–3)          (e) (–3)  × (–2)      (f) (–2)  × (–10) 5
                                                                              3
                                                                                            3
                                                                      2
                                             4
                    Solution:     (a)  2 × 10  = 2 × 10 × 10 × 10 × 10 = 20,000
                                           4
                                  (b)  0 × 7  = 0
                                              4
                                       3
                                  (c)  3  × 10  = 3 × 3 × 3 × 10 × 10 × 10 × 10 = 2,70,000
                                          4
                                  (d)  (–3)  = (–3) × (–3) × (–3) × (–3) = 81
                                                  3
                                          2
                                  (e)  (–3)  × (–2)  = (–3) × (–3) × (–2) × (–2) × (–2) = 9 × (–8) = –72
                                                  5
                                         3
                                  (f) (–2)  × (–10)  = (–2) × (–2) × (–2) × (–10) × (–10) × (–10) × (–10) × (–10)
                                                    = (–8) × (–1,00,000) = 8,00,000
                    Points to remember
                    •  A negative rational number raised to an even power is always positive.
                                         12
                                                   32
                       For example, (–1)  = 1; (–1)  = 1
                                                                                                                        55
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