Page 36 - ICSE Math 7
P. 36
3 5 3 3 15
= 8 of + × = 8 of +
5 16 2 5 32
3×32 15×5+ 96 75+
= 8 of = 8×
160 160
8 ×171 171 11
= = = 8
160 20 20 20
Example 16: Simplify the following.
3 7 3 1 1 1 1 1 1 1
(a) of + ÷ − (b) 5 − 2 + of 5 ÷ 2
19 9 4 2 3 4 3 3 2 5
1
(c) 5 of 21 + 1 ÷ 4 1 + 3 × 3
3 24 7 5 7 8
3 7 3 1 1 3 7 3 3 − 2
Solution: (a) of + ÷ − = of + ÷
19 9 4 2 3 19 9 4 6
3 7 3 1 3 7 3 6 3
⇒ of + ÷ = of + ×
19 9 4 6 19 9 4 2 1
3 7 9 3 7 × 2 +× 9 9 3 14 + 81
⇒ of + = of ⇒ of
19 9 2 19 9 × 2 19 18
3 95 3 1 95 5 5
⇒ of = × =
19 18 19 1 18 6 6
(b) 5 1 − 2 1 + 1 of 5 1 ÷ 2 1 = 21 − 7 + 1 of 11 ÷ 11
4 3 3 2 5 4 3 3 2 5
63 – 28 1 11 5 35 1 5
= + of × = + ×
12 3 2 11 12 3 2
35 5 35 + 5 × 2 35 + 10 45 15 15 3
⇒ + = ⇒ = = = 3
12 6 12 12 12 4 4 4
1 21 4 1 3 3 16 21 11 1×7 3×5 + 3
(c) 5 of + 1 ÷ + × = of + ÷ ×
3 24 7 5 7 8 3 24 7 35 8
16 21 11 7 15 + 3 16 21 11 35 5 3
= of + ÷ × = of + × ×
3 24 7 35 8 3 24 7 22 2 8
16 21 5 3 16 21 15 16 21×2 15×3+
= of + × = of + = of
3 24 2 8 3 24 16 3 48
16 42 45+ 16 87 16 87 29
= of = of = ×
3 48 3 48 3 48 3
29 2
= = 9
3 3
22