Page 34 - ICSE Math 7
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(b)  14  ÷   7   =   14  ×  25                Reciprocal of  7  is  25 
                                      15    25    15    7                                    25    7   
                                                  2 14 × 25  5  10     1
                                                =             =     = 3
                                                   3 15 × 7      3     3
                                              1
                                        2
                                  (c)  2   ÷ 1   =   16  ÷  15  =  16  ×  14        Reciprocal of  15  is 14 
                                        7     14     7   14     7   15                       14   15   
                                                           2
                                                   16× 14      32      2
                                                 =           =     = 2
                                                     7 ×15     15     15
                    Operation ‘of’
                    Quantities connected by ‘of’ denote a single quantity whereas quantities connected by multiplication
                    denote different quantities. Therefore, the operation ‘of’ is performed before multiplication.
                    Example 13: Evaluate.
                                      3                            4      5
                                  (a)    of 150               (b)    of 3
                                      5                            9  30  16

                                                  3
                    Solution:     (a)  3  of 150 =   × 150 =  3× 150     = 90
                                      5           5               5
                                              5
                                                   4
                                                                               17
                                  (b)   4  of 3   =   ×  53  =   4 ×53   =  53  = 1
                                       9     16    9   16    9× 16  4   36     36
                    Fraction as an Operator
                    A fraction can be used to operate on a quantity. In other words, when a fraction of an amount is required,
                    the fraction acts as a mathematical operator on the amount. The original amount is multiplied by the
                    numerator and divided by the denominator of the fraction. For example,
                                                 10
                        3          3        3 × 50                         2          8    13
                    (a)    of 50 =   × 50 =         = 30      (b)  2  of 39 =           × 39  = 104
                        5          5           5                           3          3
                    Continued Fraction
                                                                               1
                    A continued fraction is a complex fraction of the form           .
                                                                           3–    1 3
                                                                               1+
                                                                                  7
                    A continued fraction can be written as an expression within brackets as 1÷      3– 1÷         1+  3             .
                                                                                                          7    
                    As in simplification of expression, we start from the innermost bracket, similarly in continued fraction,
                    we start from the lowest step and then move upwards.
                                                   1
                    Example 14: Simplify 1+         1   .
                                               1+
                                                  3+  1
                                                      2
                                         1             1                            1   7 
                    Solution:     1+       1    = 1+                            3 +  =   
                                     1+      1       1+  1                          2   2 
                                                         7
                                         3+
                                             2           2

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