Page 144 - ICSE Math 7
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We can verify the result of division by using the formula:
                                                Dividend = Divisor × Quotient + Remainder

                                           2
                    Example 10: Divide x  – 75 + 10x by x – 5 and verify the result.
                                         x +  15
                                          2
                    Solution:     x – 5   x + 10x – 75
                                          2
                                                                                2
                                         x –  5x                  [ x(x – 5) = x  – 5x]
                                       –    +                      (Changing the sign)
                                               15x – 75
                                               15x – 75          [ 15(x – 5) = 15x – 75]
                                             –     +               (Changing the sign)
                                                   0

                                  Verification:

                                  Divisor × Quotient + Remainder = (x – 5) × (x + 15) + 0
                                                                       = x(x + 15) – 5(x + 15)
                                                                       2
                                                                                             2
                                                                    = x  + 15x – 5x  – 75 = x  + 10x – 75
                                                                    = Dividend
                                            2
                    Example 11:  Divide 2p  + 14 – 11p by p – 4 and verify the result.
                                          2p  –  3
                                           2
                    Solution:      p – 4  2p – 11p + 14
                                           2
                                                                                  2
                                         2p –  8p                [ 2p(p – 4) = 2p  – 8p]
                                        –    +                    (Changing the sign)
                                              –  3p + 14
                                              –  3p +  12        [ –3(p – 4) = – 3p + 12]
                                              +     –              (Changing the sign)
                                                      2


                                  Verification:
                                  Divisor × Quotient + Remainder = (p – 4) × (2p – 3) + 2
                                                                    = p(2p – 3) – 4(2p – 3) + 2
                                                                        2
                                                                                                  2
                                                                    = 2p  – 3p – 8p + 12 + 2 = 2p  – 11p + 14
                                                                    = Dividend

                                                               2
                                                                           2
                    Example 12: The area of a rectangle is 4a  – 4ab – 3b  sq. unit and its length is 2a – 3b units. Find
                                  the breadth of the rectangle.
                                                                                      2a   + b
                    Solution:     Area of a rectangle = Length × Breadth    2a – 3b   4a – 4ab – 3b 2
                                                                                       2
                                       2
                                                    2
                                  \ 4a  – 4ab – 3b  = (2a – 3b) × Breadth            4a – 6ab           [ 2a(2a – 3b)
                                                                                       2
                                                                                                                2
                                                  2
                                                4a  – 4ab – 3b 2                    –    +                    = 4a  – 6ab]
                                  ⇒ Breadth =       2a – 3b                                 2ab – 3b 2
                                  \ Breadth of the rectangle is 2a + b units.               2ab – 3b 2  [ b(2a – 3b)
                                                                                                                       2
                                                                                          –     +            = 2ab – 3b ]
                                                                                                0

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